Looking for the solution of IQ question below:
321 6
432 48
333 81
432 353
321 ?
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4$\begingroup$ [POTENTIAL SPOILER] A pattern for the first three rows: left column cell product multiplied by row index = right column cell. 3*2*1*1 = 6, 4*3*2*2 = 48, 3*3*3*3 = 81. But then for the fourth row, 4*3*2*4 = 96 != 353. :/ Also, 353 is a prime number. $\endgroup$ – SpiritFryer Jul 13 '16 at 3:40
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4$\begingroup$ Where is the image from? $\endgroup$ – f'' Jul 13 '16 at 5:48
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2$\begingroup$ Just for clarity. Are you asking for the solution of the question, or asking how one goes about to solve such a question? Your first line is slightly confusing here and might require an edit... $\endgroup$ – BmyGuest Jul 13 '16 at 6:32
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12$\begingroup$ Also noted the 4^4 + 3^4 + 2^4 = 353 $\endgroup$ – Maxqueue Jul 13 '16 at 15:56
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6$\begingroup$ I had this as an answer until z100 pointed out it was wrong: going off of @Maxqueue's comment, we see that $3^1+2^1+1^1=6$, $3^3+3^3+3^3=81$, and $4^4+3^4+2^4=353$, but $4^2+3^2+2^2=29\neq 48$. $\endgroup$ – DooplissForce Jul 13 '16 at 16:42
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How about this slightly "twisted" method?
(Yielding $276$)
- basically fudging it with what people have noted in the comments...
The number on the left has digits
$d_nd_{n-1}\cdots d_2d_1$
and is in row $r$, starting at $1$
The number on the right is whichever of $$A=\sum_{i=0}^n{d_i^r}$$ $$B=d_n^rd_{n-1}$$ is smaller after its digits have been reversed.
That would be
If $x'$ reverses the digits of $x$
Row Left A B A' B' min(A', B')' = Right 1 321 6 6 6 6 6 2 432 29 48 92 84 48 3 333 81 81 18 18 81 4 432 353 768 353 867 353 5 321 276 486 672 684 276
Not really fitting for an "IQ" test though.
answered Jul 14 '16 at 6:37
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Kind of reaching a little here but here goes:
if index is prime apply following pattern where n is the index and d is the digit:dxdxdxn If index is not prime apply following pattern where n is the index and d is the digit:d^n + d^n + d^n Therefore the answer would be: If index is prime apply following pattern where n is the index and d is the digit:dxdxdxn
Therefore the answer is:
30
Because of the fact that:
the index is 5 which is prime so 3x2x1x5=30
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3$\begingroup$ @dpwilson Still works, since $3^1+2^1+1^1=6$. :) $\endgroup$ – DooplissForce Jul 13 '16 at 16:48
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$\begingroup$ @dpwilson: Yes, but 1·2·3·1 and 1¹ + 2¹ + 3¹ are both six. $\endgroup$ – M Oehm Jul 13 '16 at 16:48
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3$\begingroup$ I hope there is a cleaner solution (I don't like the change of pattern with prime numbers) $\endgroup$ – Fabich Jul 13 '16 at 20:39
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The answer can also be
276
because you can get right hand side choosing
$$\max \left \{ nabc, a^n+b^n+c^n\right \} $$where $n$ is number of the row starts from $1$
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The answer is
6
Reasoning
Its the same as the first line (321->6). Everything else is a red herring.
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3$\begingroup$ BTW, this was tried already, and it isn't the answer. Why aren't the 432 the same then? $\endgroup$ – user58 Jul 13 '16 at 17:11
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