Looking for the solution of IQ question below:
321 6
432 48
333 81
432 353
321 ?
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Sign up to join this communityHow about this slightly "twisted" method?
(Yielding $276$)
- basically fudging it with what people have noted in the comments...
The number on the left has digits
$d_nd_{n-1}\cdots d_2d_1$
and is in row $r$, starting at $1$
The number on the right is whichever of $$A=\sum_{i=0}^n{d_i^r}$$ $$B=d_n^rd_{n-1}$$ is smaller after its digits have been reversed.
That would be
If $x'$ reverses the digits of $x$
Row Left A B A' B' min(A', B')' = Right 1 321 6 6 6 6 6 2 432 29 48 92 84 48 3 333 81 81 18 18 81 4 432 353 768 353 867 353 5 321 276 486 672 684 276
Not really fitting for an "IQ" test though.
Kind of reaching a little here but here goes:
if index is prime apply following pattern where n is the index and d is the digit:dxdxdxn If index is not prime apply following pattern where n is the index and d is the digit:d^n + d^n + d^n Therefore the answer would be: If index is prime apply following pattern where n is the index and d is the digit:dxdxdxn
Therefore the answer is:
30
Because of the fact that:
the index is 5 which is prime so 3x2x1x5=30
The answer can also be
276
because you can get right hand side choosing
$$\max \left \{ nabc, a^n+b^n+c^n\right \} $$where $n$ is number of the row starts from $1$
The answer is
6
Reasoning
Its the same as the first line (321->6). Everything else is a red herring.