Better answer by
who cannot yet make a separate answer to a protected question.
(This is a placeholder until then. Save upvotes for acushner's post.)
Sure enough,   |2|   =   2   ≤   2 .
The “$\sf\tiny NO~MINUSES$”
restriction sounds suspiciously like a clue or hint.
No minuses? Would be no problem ...
... as long as pluses are allowed, for +2 ...
... except that this turned out to be a virtual duplicate of
Max Li's (puzzle's poser's) answer
... other than they use the additional match to “draw”
(Clever—  almost anything is possible!)
Then again, don't actually need to add any matches because ...
... from Jo's perspective the matches already read
“2!” ( =   2×1   =   2 )
But if a match just has to be added,
it can be appended to get “2!!”
( =   (2!)!   =   (2)!   =   2 )
Added: “!!” in “2!!”
could more cleanly be interpreted as
giving the same result.