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The following rebus is one that should be very familiar to a great number of people, but may require an unexpected thought process.

$(\huge ma$$)\ \epsilon \ 1$
$\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \wedge$

$\small \color{red}{Note: Mathjax\ displays\ differently,\ per\ computer\ resolution,\ so\ here\ is}$
$\small \color{red}{what\ the\ question\ should\ look\ like\ if\ you're\ having\ trouble.}$

Picture with arrow correctly pointing at the 1.

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  • $\begingroup$ postimg.org/image/kxdmrk5fl Solvable or no? If not please provide a picture of the desktop version $\endgroup$
    – warspyking
    May 18 '16 at 22:32
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    $\begingroup$ @warspyking looks like it does on my desktop $\endgroup$
    – Jonathan Allan
    May 18 '16 at 22:32
  • $\begingroup$ @Jonathan Allan Awesome :D $\endgroup$
    – warspyking
    May 18 '16 at 22:36
  • $\begingroup$ Aww... I was hoping this was a Rogue Squadron puzzle. $\endgroup$
    – LeppyR64
    May 18 '16 at 23:23
  • $\begingroup$ :) @LeppyR64 hehe $\endgroup$
    – Khale_Kitha
    May 18 '16 at 23:24
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The answer is:

The force is strong with this one.
- Darth Vader

Force = mass * acceleration (ma)

The (ma) is really big and strong.

The epsilon is for sets. The (ma) is with the 1.

The 1 is "one" and the arrow (or wedge) is pointing to "this one".

Interesting note: In the edit text the up arrow is called a wedge. The OP has a hidden comment in the text that says:

No, Biggs and Wedge aren't part of this. Quit looking at the edit screen.

It's a reference to two of the pilots that flew with Luke in Red Squadron.

Rogue Squadron was a group formed by Luke for doing other missions.

The Rogue Squadron book series that came out in the 90's. Now I have my summer reading set of me.

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  • $\begingroup$ I thought that, but the epsilon?? $\endgroup$
    – Jonathan Allan
    May 18 '16 at 23:43
  • $\begingroup$ Yeah I can't explain it yet either :) $\endgroup$
    – LeppyR64
    May 18 '16 at 23:49
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    $\begingroup$ Maybe OP meant to use \in rather than \epsilon? Wait, that's still not a with... $\endgroup$
    – ffao
    May 19 '16 at 0:05
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    $\begingroup$ I think this must be right; perhaps the OP misremembered the quotation as "... in this one". (The set-membership symbol was actually originally an epsilon, short for "is" in Latin, Greek, etc.) $\endgroup$
    – Gareth McCaughan ♦
    May 19 '16 at 0:15
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    $\begingroup$ @GarethMcCaughan I find your lack of faith (in OP) disturbing ;) $\endgroup$
    – LeppyR64
    May 19 '16 at 0:35
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How about

"This little one's not worth the effort" (Obe-Wan Kenobi)?

Since

The arrow, this, points to the one, epsilon means a small quantity, a range in parentheses does not include the endpoints, $F=ma$ force is effort.

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Not sure about this, but is it:

Force multiplier? ma could stand for mass x acceleration which is the equation for force. The arrow is pointing at the space between the epsilon and the 1 which in mathematics implicitly indicates a multiply operation.

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  • $\begingroup$ The arrow is intending to point at the 1. The syntax didn't allow further design precision. $\endgroup$
    – Khale_Kitha
    May 18 '16 at 23:28
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    $\begingroup$ Oh, gotcha. You might want to note that in the question. $\endgroup$
    – Tonkleton
    May 18 '16 at 23:31

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