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This is the second question in the series: The Gnosis questions

"Since people look at round figures with suspicion,
They added two, to an Indian's estimation for a foreigner named object.
Look, it's slowly walking away from you..."
What is it(the object)?

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  • $\begingroup$ No, it doesn't. But, I'll be adding a hint soon. $\endgroup$
    – ABcDexter
    Apr 18, 2016 at 4:25

2 Answers 2

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I think it is :

Mount Everest

Because

In 1856, the Great Trigonometrical Survey of India established the first published height of Everest, then known as Peak XV, at 29,002 ft. It was calculated to be exactly 29,000 ft high, but was publicly declared to be 29,002 ft in order to avoid the impression that an exact height of 29,000 feet was nothing more than a rounded estimate.

https://en.wikipedia.org/wiki/Mount_Everest

I don't have an answer for "Look, it's slowly walking away from you" - unless someone quoted this when adding the 2 feet.

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    $\begingroup$ This seems very likely, nice work $\endgroup$ Apr 18, 2016 at 13:26
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    $\begingroup$ The 'slowly walking away' might have something to do with tectonic plate movements? $\endgroup$ Apr 18, 2016 at 14:15
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    $\begingroup$ Thanks - I'd heard about the height measurement before- - hope the rest of answer is OK or Tim's suggestion may be the one. $\endgroup$
    – Tom
    Apr 18, 2016 at 15:12
  • $\begingroup$ Well worked, kudos ^_^ $\endgroup$
    – ABcDexter
    Apr 18, 2016 at 16:14
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Is the Object

PI (π) the mathematical constant

reason

Since people look at round figures with suspicion

Its very hard to have very accurate measures for round shaped objects due to the value of PI

They added two, to an Indian's estimation for a foreigner named object

Chinese mathematician had approximated the values up to 7 decimal places which is places more than Indian mathematician's approximation up to 5 decimal places. Also the name of PI is not aboriginal to India and China either.

Look, it's slowly walking away from you..."

Its values has not been fixed yet and you can keep on computing it

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  • $\begingroup$ A very good guess, i'd have accepted it as the correct one O:-) $\endgroup$
    – ABcDexter
    Apr 18, 2016 at 21:02

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