Can you add 2 numbers to this pattern ?


Hint 1

The first part of this pattern is certain but the answer is not

Hint 2

You can only add 2 numbers at the end at the moment. But if you take too much time to solve this, you may have to find more...

  • 2
    $\begingroup$ Of course, I can add like a million numbers to it. Are we completing a pattern? At the end? The beginning? Digits in the middle? $\endgroup$ Apr 11 '16 at 17:52
  • $\begingroup$ @Raystafarian I have added a new hint and a new tag, I hope it is clearer $\endgroup$
    – Fabich
    Apr 11 '16 at 18:44
  • $\begingroup$ Could you tell us what kind of knowledge we need? Or would it make it too easy for us? $\endgroup$
    – Shuri2060
    Apr 11 '16 at 21:21
  • $\begingroup$ Interpreting these as post IDs seemed to lead somewhere, but they point to a lot of deleted posts. Both the second and the third (now deleted) are answering "decimal point" to two different questions though... $\endgroup$
    – Deusovi
    Apr 11 '16 at 22:46
  • $\begingroup$ @Deusovi Since OP doesn't have 2000 rep to view deleted posts, I don't think that's on the right track. $\endgroup$
    – f''
    Apr 11 '16 at 23:41

The numbers mean

10730 days after 1/1/1970: May 19, 1999
11823 days after 1/1/1970: May 16, 2002
12922 days after 1/1/1970: May 19, 2005
2701 days after 1/1/1970: May 25, 1977
3793 days after 1/1/1970: May 17, 1980
4892 days after 1/1/1970: May 25, 1983
16787 days after 1/1/1970: December 18, 2015

The next two numbers may be

December 15, 2017: 17515
May 24, 2019: 18040

  • 1
    $\begingroup$ The last one could be 17151. Great job, by the way +1 $\endgroup$
    – dmg
    Apr 12 '16 at 7:04
  • $\begingroup$ You are right ! $\endgroup$
    – Fabich
    Apr 12 '16 at 7:20
  • $\begingroup$ What is the reason for the next two numbers? $\endgroup$ Apr 12 '16 at 7:30
  • 1
    $\begingroup$ I actually tried this except counting away from the present date, not from an arbitrary date. Nice job finding this, turned the question from negative to positive which wouldn't have happened if this went on for a week :) $\endgroup$
    – Quark
    Apr 12 '16 at 8:01
  • 2
    $\begingroup$ @Quark The date is not arbitrary, see en.wikipedia.org/wiki/Unix_time But I did have the distinct advantage that I actually found the answer first (from the patterns in the sequence that should be obvious in hindsight), then reverse engineered the code $\endgroup$
    – ffao
    Apr 12 '16 at 8:05

Not an answer but an idea:

Considering the hint "You can only add 2 numbers at the end at the moment. But if you take too much time to solve this, you may have to find more..." and the knowledge tag, I suspect that the answer has to do with occurrences of something.

7 occurrences are listed, and we can only list 2 more (at the moment). Therefore we are looking for something that has happened 9 times...

Those numbers could represent dates, or could encode information about these events in some way. Although this idea hasn't gotten me anywhere yet, I'm thinking things like comet appearances, presidents... but I can't really get anywhere without knowing what kind of knowledge is needed.


However, looking at the 1st hint, it says we cannot be sure about the answer, although we can about the 1st part of the pattern. Perhaps this means 7 occurrences have taken place, whilst the 2 we can put for the answer are the next ones predicted which have not happened yet, and we aren't able to predict any more (for whatever reason).

  • $\begingroup$ You are on the right way ! Think about how you can group the numbers and the order $\endgroup$
    – Fabich
    Apr 11 '16 at 21:42
  • $\begingroup$ This was my first instinct as well, but I cannot get anything significant to match between them. The last entry, 16787, indicates that the only possible format for a legitimate Gregorian date as D(D)M(M)YY. $\endgroup$ Apr 11 '16 at 22:53
  • $\begingroup$ What if the numbers are in pairs? $\endgroup$
    – stackErr
    Apr 12 '16 at 2:54

maybe the two numbers are:



look at the first 3 numbers they are separated by 1093 and 1099
look at the second batch of three numbers they are separated by 1092 and 1099
so at the third one they must be separated by 1091 and 1099 it could be back to 1093 and 1099 but the hint says they are not the same so it must be different.

  • 1
    $\begingroup$ Please explain why! $\endgroup$ Apr 11 '16 at 18:01
  • $\begingroup$ @crybaba No, sorry ;) $\endgroup$
    – Fabich
    Apr 11 '16 at 18:15
  • $\begingroup$ @crybaba This does not match the hint about uncertainty $\endgroup$
    – Fabich
    Apr 11 '16 at 18:34
  • 1
    $\begingroup$ Does it have to do with US tax forms? $\endgroup$
    – Z. Dailey
    Apr 11 '16 at 20:22
  • $\begingroup$ @Z.Dailey no it doesn't $\endgroup$
    – Fabich
    Apr 11 '16 at 20:53

Something I saw:

If you divide the numbers by 365 (days in a year) you get some unique numbers:


So whatever event it is, it seems linked to a solar cycle. By looking at the three clumps, it seems like crybaba's answer of 17878, 18977 could be close to the real answer.


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