13
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Let x be the answer.

Given that x is:

  1. Associated with a baroque painter and an ungulate
  2. A possibility to be faced by half of us
  3. Similar in sound to having been served a beverage

And the following equation holds true:

(x - DROPLET) + (x - MINSTREL) + (x - CANIFORM_CREATURE) = RAINBOW_EDGE

Solve for x and explain the clues.

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  • 2
    $\begingroup$ rainbow edge could be red or violet? $\endgroup$ – Beastly Gerbil Apr 10 '16 at 17:39
  • $\begingroup$ A possibility facing half of us could be something that only men or only women experience. Could it be childbirth? Or period? $\endgroup$ – Richard Roe Apr 10 '16 at 17:54
  • $\begingroup$ @Richard Roe: Or color blindness. Or endometrial cancer. Or menopause. $\endgroup$ – Gamow Apr 10 '16 at 17:58
  • $\begingroup$ @Gamow On the other hand, this could be a cryptic crossword style clue, meaning half of the word "us" that is, "u" or "s". I don't see how this would work, though. $\endgroup$ – Richard Roe Apr 10 '16 at 18:00
11
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x is:

BEARD

  1. Associated with a baroque painter and an ungulate

    A Van Dyke and a goatee
    (thanks to Wikipedia for the first one)

  2. A possibility to be faced by half of us

    Only men can possibly have one

  3. Similar in sound to having been served a beverage

    "BEER-ED" (is there really such a word?)

Equation:

(BEARD - BEAD) + (BEARD - BARD) + (BEARD - BEAR) = R + E + D = RED

Title:

Beard is made of hair which is a protein filament
(thanks to @Hugh for the link)

Credit to @manshu for steering me towards anagrams.

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  • 1
    $\begingroup$ For the first half of clue 1, I would guess: en.wikipedia.org/wiki/Van_Dyke_beard $\endgroup$ – Gamow Apr 10 '16 at 19:24
  • $\begingroup$ You want the bearded pig (sus babyrus) for clue 1 $\endgroup$ – frodoskywalker Apr 10 '16 at 19:25
  • $\begingroup$ @Gamow: Just found that on Wikipedia a few minutes ago. ;) $\endgroup$ – KeyboardWielder Apr 10 '16 at 19:26
  • 1
    $\begingroup$ Guess what it's made of? en.m.wikipedia.org/wiki/Hair $\endgroup$ – Hugh Meyers Apr 10 '16 at 19:32
  • 1
    $\begingroup$ @Knight0fDragon: But I know the 3rd man. :) Don't worry, I'm not arguing either, just kidding around... $\endgroup$ – KeyboardWielder Apr 10 '16 at 20:05

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