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I play a role-playing game set in a modern fantasy universe. When the Game Master cannot attend he likes to set us puzzles instead. If we can crack them we earn extra experience... we have never cracked a single one. If someone could help me solve one for a change I would be very appreciative! Below is all the information we have been given:

While sleeping in the Dark Forest, Erin dreams of whispers, hearing Leonardo's voice, he wakes up frantically and begins scribbling numbers on a wall. Waking up the next day, you realize they seem to make little sense, but maybe Leonardo's trying to tell you something...

208519211720211391811229612101514221916220  
23713141763244158525616918723721  
8151016111425222111781223198171291026  
132723282421131892922251424111419152010252032616111230
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    $\begingroup$ At the beginning, 20 8 5, are the positions of the letters T H E in the alphabet. I can't get it to make a lot of sense beyond that, though. $\endgroup$
    – GentlePurpleRain
    Apr 8, 2016 at 20:37
  • $\begingroup$ Nevermind, I misunderstood what you wrote, GPR. I have a different thought.. $\endgroup$
    – Khale_Kitha
    Apr 8, 2016 at 20:43
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    $\begingroup$ I don't think that is the pattern. The last two characters are 30, so you would either have C and nothing, or a non-existent letter. $\endgroup$
    – APrough
    Apr 8, 2016 at 20:46
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    $\begingroup$ Could 0 equate to being a full stop? $\endgroup$
    – Callum West
    Apr 9, 2016 at 9:59
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    $\begingroup$ How 'evil' is your GM? "...we have never cracked a single one" Do you have proof that there is a solution to those ? Just asking because I know some very mean GMs ;-) $\endgroup$
    – BmyGuest
    May 21, 2016 at 23:16

2 Answers 2

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The first line goes to something like this:

20 8 5 T H E

19 S/AI

2117 UQ/UAG/BAAG/BKG/BAQ

20 T

2113 UM/UAC/BKC/BAM/BAAC

9 I

18 R/AH

1122 KV/ALB/AAV/KBB/AABB

9 I

6 F

12 L/AB

10 J/A

15 O/AE

14 N/AD

2219 VS/VAI/BTI/BBS/BBAI

16 P/AF

220 BT/BB/V

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Not sure how much help it is, but I got the frequency set, just to rule out some existing ciphers.

  • 0: 10

  • 1: 50

  • 2: 39

  • 3: 11

  • 4: 9

  • 5: 10

  • 6: 9

  • 7: 8

  • 8: 9

  • 9: 10

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  • $\begingroup$ This digit frequency fits the profile of English text, enciphered with a polyalphabetic cipher (such as Vigenere), then encoded with A1Z26. It also fits the profile of uniformly random letters from A-Z encoded with A1Z26. $\endgroup$
    – codewarrior0
    Jun 19 at 6:37

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