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The gun is loaded with a single bullet. You go first, and I always win.

How is this possible?

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    $\begingroup$ Winning once qualifies you as "always" winning against me. $\endgroup$ – Will Apr 7 '16 at 7:25
  • $\begingroup$ yeah i forgot that bit. 'you' is in the abstract :) $\endgroup$ – JMP Apr 7 '16 at 7:25
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    $\begingroup$ you don't say what the rules are for "winning". Maybe in your sick head, you just like it when people die and you don't care if it is even yourself :P So whoever gets shot is a "win" for you $\endgroup$ – Ivo Beckers Apr 7 '16 at 7:54
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    $\begingroup$ Russian roulette is defined as the practice of loading a bullet into one chamber of a revolver, spinning the cylinder, and then pulling the trigger while pointing the gun at one's own head. If you are not using a revolver, the game is no longer called Russian roulette. It's simply forced suicide. $\endgroup$ – CodeNewbie Apr 7 '16 at 8:05
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Solution:

The gun is not a revolver, but a pistol with a bullet in the chamber. The one pulling the trigger first is bound to lose.

By 'pistol' I mean any handgun where the single chamber is integral with the barrel.

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  • $\begingroup$ if by 'pistol' you mean the old-fashioned type.. i was thinking >! imfdb.org/wiki/Single_Barreled_Shotgun $\endgroup$ – JMP Apr 7 '16 at 7:29
  • $\begingroup$ Something like that, I updated my answer. $\endgroup$ – Block Apr 7 '16 at 7:33
  • $\begingroup$ That would make it something other than Russian Roulette. $\endgroup$ – Richard Roe Apr 7 '16 at 18:09
  • $\begingroup$ @RichardRoe, you are completely right and I agree. However, as confirmed by the question asker, this alteration of rules was the 'twist' $\endgroup$ – Block Apr 8 '16 at 6:23
  • $\begingroup$ @Block Oh. Sorry I can't take away the downvote. $\endgroup$ – Richard Roe Apr 8 '16 at 18:41

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