7
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This is an old favorite of mine...

Can you find the answer?

$(a-x)(b-x)(c-x)(d-x)...(z-x)=?$

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  • $\begingroup$ I am damn sure that this is a duplicate question. I have seen the same question here at the early stages of the puzzling.stackexchange. $\endgroup$ – AeJey Mar 31 '16 at 13:12
10
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Answer:

$0$

Reasoning:

As $(x-x)=0$ and $0$ multiplied by any number is $0$.

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  • $\begingroup$ Oh you posted just seconds before I did. I'll remove my answer. $\endgroup$ – Ghapla Mar 31 '16 at 10:22

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