0
$\begingroup$

Losing my whole Keychain has hit me hard. Thankfully, the SE community has been extremely helpful. Here's another one I need to find. This one is the passcode for my iPad. It's 6 digits.

No password hint on this one.

The process I used to get to the password (stored in my email, thankfully).

When I started to reach up high
I dreamt I'd reach the highest sky
Square a square and it would be
Yet the moon's days still elude me.

Improve this question
$\endgroup$
8
$\begingroup$

Is it:

614656

When I started to reach up high
I dreamt I'd reach the highest sky

At 614656m you are in the exosphere (the outer layer of the atmosphere)

Square a square and it would be
Yet the moon's days still elude me.

The moon goes in cycles of 28 days and (28^2)^2 is 614656. Squaring a square of the "moon's days" or days in a moonth.

Improve this answer
$\endgroup$
  • $\begingroup$ I like the direction of your thinking here. Just a note that the moon's day/orbit cycle is just over 27 days rather than 30 which throws the exosphere numbers out. $\endgroup$ – Samthere Mar 18 '16 at 12:58
  • $\begingroup$ I was going more along the "moonth" logic so let me adjust numbers. Also still in exosphere above 500km. $\endgroup$ – Z. Dailey Mar 18 '16 at 14:25
  • 1
    $\begingroup$ ~29.5 days, but lunar cycles, months, and moonths have never been quite in agreement. It's something between 28 and 30 which I believe would result in the answer you're looking for. Hence the reason I first chose 30 as 29.52... Rounds to 30 and an irrational number would not result in a 6 digit code. $\endgroup$ – Z. Dailey Mar 18 '16 at 17:54
  • 1
    $\begingroup$ The lenght of a lunar cycle might be 27.555 or 27.322 or 27.212 or 29.531, depending on whether you use the anomalistic, sidereal, tropical, draconic, or synodic version: en.wikipedia.org/wiki/Lunar_month . $\endgroup$ – Gamow Mar 18 '16 at 18:03
  • 1
    $\begingroup$ Exactly, so without further hint, I don't believe it's solvable (without a total guess) unless there is something in those 4 lines that was completely missed. $\endgroup$ – Z. Dailey Mar 18 '16 at 18:06

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.