Based on @Khale_Kitha's partial answer...
Alphametics?
Let's turn things on their sides...
$$II \ge II$$
$$II - I > I$$
$$XI - II > II$$
$$MM x MM = CCXX$$
$$CC - II \ge XX$$
$$MC - CX = ????$$
$$????$$
$$????$$
So the last line seems like it could be 1100, 1, and 110 (MC - CX = MC - CX?)
Solving time!
The only valid value for $M$ is $8$; $C$ is $7$ and $X$ is $4$
Because $$77 - 44 \ge II,$$
I = $1$ or $2$ or $3$
Because $XI - II > II$, $X > 2*I$, so $I = 1$
Last line: $MC - CX = 87 - 74 = 13$
The second number must be a plus or minus, but we have no minus, so #2 is $I$ (1)
The last line must be 87 - 74 or 84 - 71
The 3 numbers are $MC, I, CX$ (1100 1 110) or $MX, I, CI$ (1010 1 11)
All of that said, I like feelin's answer, and I hope I made a mistake! :P