Ok, so my friends and I had a disagreement over this seemingly simple problem and we would very much like to know the answer for it.
Initially a 100 kgs watermelon is 96pc water and 4pc pulp. After keeping it out in the sun for (say X) hours, the watermelon is now 95pc water. What is the weight of the watermelon now?
The mass of watermelon pulp initially was 4kgs. So equating that to 5pc of the current distribution would be 5/100*weight = 4kgs => X = 80Kgs
Assume it's a 100kg watermelon. Answer 1 is wrong as only 95pc of the 96pc water is now available. You've lost 5pc water of 96pc = 5/100* (96pc *100) = 4.8kg water. So water's total weight now is 96 - 4.8 = 91.2 kg + 4kg pulp = 95.2kgs
Can someone please explain? Thanks!