# 200 Discs - weighing problem

You are an intrepid explorer who has been caught in a trap by a primitive tribe. They lock you in a room with no exit but one door. The door has a pressure sensitive release - incorrect pressure ($>0g$) will cause immediate death. There are 10 piles each of 20 heavy stone discs (200 in total). You know what each disc should weigh (I can tell you that the number is in whole grams).

You have some facts:

• You know that one of the piles is made of discs that are missing 15.5 grams of the normal weight of a disc.
• You also know that another distinct pile is made of discs that are missing 6.5 grams of the normal weight.
• You also know that all the discs in all the other piles weigh exactly the right amount.

You have weighing scale (non-balancing) that is accurate to the gram.

The tribe leader has set the rules. You must determine which piles are normal, which pile is off by 15.5 grams and which is off by 6.5 grams using the scale only once. Only by putting one disc from each of the 2 piles which are not normal on the pressure pad to release the door will you survive.

• What is "exactly the right amount" or the total weight of a normal pile? – warspyking Oct 8 '14 at 23:11
• Not telling.... – d'alar'cop Oct 8 '14 at 23:12
• Is this a duplicate of Coin weighing problem? – user20 Oct 9 '14 at 0:06
• @Emrakul It appears to be a slightly more complicated variant – d'alar'cop Oct 9 '14 at 0:14
• Hence me listing it as a spinoff, not a duplicate :) – Tim Couwelier Oct 9 '14 at 12:20

Since we know what each disc should weigh ($n$), we can weigh 1 disc from pile 1, 2 from pile 2, etc (10+9+8... = $55n$). However, since some weights are half-grams, we'll need to double up instead (20+18+16... = $110n$).