Think about a circle that is 1 unit in circumference, and just north of the South Pole. We’ll call that C(1).
If you are 1 unit north of this circle, then you will also end up back at the same spot. You will travel one unit south, then you’ll travel one unit around the circle, and then you’ll go north and end up back at the same spot as you started.
Actually this is true for any point on the circle that is 1 unit north of C(1). So this is an infinite number of solutions.
Infinity times infinity!
Now think about a circle that is 1/2 unit in circumference and also just north of the South Pole. We’ll call that C(1/2).
If you are 1 unit north of this circle, then you will also end up back at the same spot. You will travel one unit south, then you’ll travel the circle TWICE, and then you’ll go north and end up back at the same spot.
Similarly, if you are one unit north of the circle C(1/3)–a circumference of 1/3 near the South Pole–then you will also end up back at the same spot. You will travel around C(1/3) a total of 3 times.
We can use the same argument for C(1/4), C(1/5), and so on for any C(1/n), where each circle has a circumference of 1/n. If you go one unit west in any of these circles, you will travel around the circle n times and end up back at the same point.
Therefore, you will always end up at the same spot if you are one unit north of any circle C(1), C(1/2), C(1/3), etc.
There are an infinite number of C(1/n) circles, and you can be anywhere on the circle one mile north of each circle.
So this is basically infinity times infinity points.
In conclusion
!The complete solution is you can be:
one unit north of C(1) (infinity points)
one unit north of C(1/2) (infinity points)
one unit north of C(1/3) (infinity points)
…
one unit north of C(1/n) (infinity points)
…
So this is basically 1 + (infinity)(infinity).
So no, according to this conclusion you wont be able to find him.