# 20 coins on the table

Two boys , Brian and Gabe, decide to play a game.

They lay 20 coins on the table. Each player took turns taking 1, 2, or 3 coins. Whoever took the last coin won.

Brian thought if he went first, he'd win for sure since he had the advantage of making the first move. So Brian did go first. But Gabe won every time!

Obviously Gabe had a winning strategy, but what was it? Could Brian have outsmarted it?

• Great answer! Player 1 can win in any other case situation because he can just make the coins a multiple of 4. Remember that any amount of coins have the form $4n,4n+1,4n+2,4n+3$ – durum Oct 6 '14 at 10:27