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Ok, so I run a play-by-post RPG campaign and I have the following "puzzle" set out for the group. My main worry is that they won't get it so I figured I'd try it here first. Other than solving it, I'd also love it if you could give indications of what got you through it, what things are too obvious, etc. and if you think it's too hard for novice puzzlers :)

I doubted for a while if I should post it here or over at RPG SE, but in the end I feel this is mostly a puzzle question. This is an edited version of the puzzle so that when they google it they wont go immediately here.

Short bit of prestory: It's 27th April 3577 AF, You're an inquisitor in training, in a foreign land investigating. During the night, your mentor suddenly left and all he did was leave you a note. The note is in his handwriting but the content is very much not in his style. You notice there's some odd misspellings in the letter that form the word hidden, and when you investigate further you notice the second letter of each word spells out that you should look in his dresser. In his dresser, in a secret compartment you find another scroll, completely jibberish apart from the top line, and a necklace.

The note reads:

see you again in 12 years

aew tprhowi  se wlindao,s trth e isn aglnccecpaot o ntudp o.sernet e mact twhhhiay  no cnlu tyl srbek pne yobyr oeslfuf.dhem eae wI tn es edIroc ae n abv liaet  ucot .kyo          

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  • $\begingroup$ My suspicion, based on the fact that no one has yet answered your question, is that it is probably too hard. This is an excellent place to ask your question, though. Please don't be deterred by the fact that you've had too many responses. Perhaps you want to consider posting the answer to the puzzle yourself, and requesting feedback on ways to improve it? (That might work best in a separate question, if you choose to do it.) $\endgroup$ Commented Jan 5, 2016 at 15:51
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    $\begingroup$ Based on the ciphertext and the note, I'm guessing it is a kind of permutation/transposition cipher somehow based on the date 3601/04/27. $\endgroup$ Commented Jan 5, 2016 at 17:03
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    $\begingroup$ I tried some different column/row transposition ciphers with 2 7 0 4 3 5 8 9 (and 3 5 8 9 0 4 2 7) as key, also along with the key 13 4 2 10 11 0 2 4 (spelling necklace), but with no luck. I'm guessing the necklace is also part of the key, but it might just be a red herring. There are 3 periods but only two captial letters, which is somewhat confusing. $\endgroup$ Commented Jan 5, 2016 at 18:51
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    $\begingroup$ I'm not completely sure what 'Age of Frank' means... $\endgroup$ Commented Jan 5, 2016 at 19:35
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    $\begingroup$ @CarlLöndahl i updated the post to make sure there's no formatting weirdness being done to make you have the wrong text, the cipher is correct as well, if you use the link i gave you should have it. $\endgroup$
    – DrunkWolf
    Commented Jan 5, 2016 at 21:41

1 Answer 1

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The solution is

what power lies in words, that a single concept can outdo. present me that which can only truly be spoken by yourself. feed me what I need so I can reveal it back to you.

Step 1

The first step is to determine the type of the cipher. The site from Simon Singh has a nice tool to determine the frequency of the letters in the cipher text. It also shows the expected count of letters for an English text, which leads to the conclusion that no substitution was used.

enter image description here

Difficulty of this step: easy.

Step 2

As we don't use a substitution cipher, the next guess is that some kind of transposition is used. There is another nice site for this kind of ciphers. The text has a length of 170 characters. Prime factors of 170 are 2, 5 and 17, so testing the corresponding numbers for rows and columns first makes sense, if we assume that the riddle was designed to be not too hard. Arranging the cipher text in 10 columns and 17 rows gives this table:

enter image description here

The correct key for this part was already posted in the comments above. Another method to solve this without a key would be to use an anagram solver with an appropriate row. In this case I used the 5th row containing the word "concept". Having most of the columns correct, the rest is then pretty easy:

enter image description here

Some other properties of the cipher text can also be used to find out the correct ordering. In the last row the period should be in the last column. Other periods and the comma should be followed by a blank. Making the starting letter of the next sentence a capital letter could be already enough to solve the rest without a key.

The key used is presented as a date in the text of the riddle: 27th April 3577 AF. Adding the 12 years from the note and using 1 and 6 for A and F gives the complete key.

Difficulty of this step: hard to say because of the leaked key in the comments, but I would say medium.

Additional thoughts

The difficulty rating I've given is of course subjective. There are much harder crypto puzzles on this site. It's also an interesting topic, so I know some simple cipher methods. If your audience never heard of "letter frequencies", already the first step might become unsolvable. Finding the correct number of rows/columns also involves some amount of trial and error. Presenting the cipher text in a correctly sized grid would make the deciphering much easier, definitely too easy if someone made some code cracking before.

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    $\begingroup$ Excellent work. But surely you have one step left? What is the answer to the riddle given? $\endgroup$
    – Dr Xorile
    Commented Jan 6, 2016 at 0:35
  • $\begingroup$ Great answer! Thanks for your efforts describing how you got there as well. Do you feel there's any obvious changes I can do to make it more accessible? I've been wondering if I should use capital letters at start of the sentences, to make it easier to see what cipher was used. Do you have any clue what word the deciphered riddle has for solution? $\endgroup$
    – DrunkWolf
    Commented Jan 6, 2016 at 0:45
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    $\begingroup$ @DrunkWolf Oops, I didn't realise there is a riddle left to solve. I'm afraid I have no idea for that part yet. Does it have something to do with the "inquisitor" part of the question? Regarding your other questions, I have added some comments to my answer. $\endgroup$
    – Sleafar
    Commented Jan 6, 2016 at 7:25
  • $\begingroup$ @Sleafar it does yes, but i guess this riddle gets a lot easier with more player knowledge. But yes, something to do with inquisition and a single word answer $\endgroup$
    – DrunkWolf
    Commented Jan 6, 2016 at 10:45

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