One for the front
Two for the back
You will never need three.
What is this?

I thought it might be personality.

  • 1
    $\begingroup$ Just to clarify, I thought it might be personality. is not part of the riddle right? :P $\endgroup$
    – DrunkWolf
    Oct 22, 2015 at 13:46
  • 4
    $\begingroup$ To add more to DrunkWolf's question, does this mean you don't know the answer? $\endgroup$
    – Aggie Kidd
    Oct 22, 2015 at 13:51
  • $\begingroup$ Rolled back because I'm unsure whether the edit removes important information, and would rather leave it to OP to decide. $\endgroup$
    – user20
    Oct 22, 2015 at 19:38

4 Answers 4


The answer is:


(one to see your front; two to see your back; you never need three)


It's the letter 'o'.
At the front of 'one', at the back of 'two' and none in 'three'.

  • $\begingroup$ Clever, but I think it would be "you'll never need it for three" - the way it's written now, it makes no sense. $\endgroup$
    – Deusovi
    Oct 23, 2015 at 13:14

This is

a tricycle. 1 wheel in front, two in back. You would never need three wheels in either position.

  • $\begingroup$ What do they call those things that have 2 wheels in the front and 1 in the back? $\endgroup$
    – John Odom
    Oct 22, 2015 at 19:43
  • 1
    $\begingroup$ @JohnOdom en.wikipedia.org/wiki/Tricycle according to wikipedia it's called a tadpole tricycle. The more common example I references being called a delta tricycle. $\endgroup$ Oct 22, 2015 at 19:52

Potential answer:

http://onlineslangdictionary.com/meaning-definition-of/number-one <-- see the first example, don't need a 3.

  • 3
    $\begingroup$ Might be a good idea to edit that information into your answer. Currently it's link-only. $\endgroup$ Oct 23, 2015 at 9:04
  • $\begingroup$ I think the answerer is shy of incorporating the explicit answer into the question because it is, hm, not really decent =) $\endgroup$
    – syck
    Oct 23, 2015 at 14:54
  • $\begingroup$ Yeah I thought at first it probably wasn't the intended answer anyway but now I'm starting to think it may be. I'll delinkify it if that turns out to be the case =) $\endgroup$
    – Quark
    Oct 26, 2015 at 8:48

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