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A big cube is cut into 99 smaller cubes. Exactly 98 of these 99 smaller cubes are unit cubes.

Question: What is the volume of the big cube?

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Hm...

Let $k$ denote the side length of the non-unit cube. We know $k>1$ because if it weren't, then there couldn't be a cube, and for the same reason we know $k\in\mathbb{N}$.

Let $n$ denote the length of the full cube. This means $n^3-k^3=98$.

That factors into $(n-k)(n^2+nk+k^2)=98$; the only factors of 98 that produce an integer value for $n$ and $k$ are 2 and 49. This makes $n=5$ and $k=3$.

So the volume of the full cube is 125 cubic units.

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    $\begingroup$ You can factor $n^3-k^3$ as $(n-k)(n^2+nk+k^2)$ and then try each of the possibilities for factoring 98. Only $2\times49$ provides an integer solution. $\endgroup$ – f'' Oct 18 '15 at 15:52
  • $\begingroup$ @f'': Right, I always forget about the difference of cubes factorization. That would definitely make it easier. $\endgroup$ – Deusovi Oct 18 '15 at 16:03

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