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While messing around at one evening, I made six small drawings, one for each friend of mine.

My drawings were made to be very specific: Taking the action or object represented in any of them, you can rip out all the non-alphabetic characters, then discard one letter to yield the respective friend's first name.

For example, if I had drawn something like this:

PuzzleExample

You could expect it's talking about marriage, so "marry" would be the action, yielding, among some unusual names, "Mary". Happily, all my friends' names are in what is considered the "normal" spectrum.

Can you guess their names only from the drawings below?

Friend 1:

Puzzle 0

Friend 2:

Puzzle 1

Friend 3:

Puzzle 2

Friend 4:

Puzzle 3

Friend 5:

Puzzle 4

My greatest friend (And love):

Puzzle 5

Note: The order has changed because of one drawing that I forgot to add to the list.

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    $\begingroup$ Can't understand if in N°2 there is a ribbon or a fly :( $\endgroup$
    – Narmer
    Commented Sep 24, 2015 at 9:44
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    $\begingroup$ In N°2, is there a butterfly or a bow tie? $\endgroup$
    – Gamow
    Commented Sep 24, 2015 at 10:35
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    $\begingroup$ N°1 is clearly a leash and bow on an invisible dog. Not sure what name that implies, but pretty sure that's the intent... (I assume you both meant that? N°2 is not anything like a ribbon, fly, etc.) $\endgroup$
    – Darrel Hoffman
    Commented Sep 24, 2015 at 14:19
  • $\begingroup$ @DarrelHoffman Well... I had to economize considering my limited time and drawing skills... $\endgroup$
    – MathET
    Commented Sep 24, 2015 at 14:23
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    $\begingroup$ The first one gives me "outhouse" instead of "marriage" $\endgroup$
    – Alex
    Commented Sep 24, 2015 at 14:57

9 Answers 9

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For number two:

The invisible dog comment is spot on. But because the dog is not there, what you are left seeing is the leash. Drop an S and you get: Leah.

For number three:

I think that Gordon K went too far. It shows an atom, and dropping one letter gives us a very "normal" name: Tom.

For number five:

It seems pretty apparent from the drawing that the K is transparent. In other words, a "clear K". Drop the E and you have: Clark.

For number four:

You are putting the R in the E can. In other words, "can the R in E". Lose the first N and you have: Catherine.

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  • $\begingroup$ Both correct. Congratulations! $\endgroup$
    – MathET
    Commented Sep 24, 2015 at 17:33
  • $\begingroup$ One more, also correct. Keep going! $\endgroup$
    – MathET
    Commented Sep 24, 2015 at 18:07
  • $\begingroup$ Three down, three to go :) $\endgroup$
    – Dylan Cristy
    Commented Sep 24, 2015 at 18:09
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Number 2 shows:

An atom of hydrogen with an electron A, a proton B and uncertainty over whether there is a neutron C. The verb could be analyze stable hydrogen isotopes (ASHI) and dropping the letter 'i' gives Ash. Ok, I know this is a bit of a stretch.

Number 4 shows:

'K' on a disc, so the verb would be 'disc K'. Drop the letter 's' to get Dick.

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  • $\begingroup$ Is Dick a common first name in the US? Searching it only yields the surname which is most common in Scotland $\endgroup$
    – MathET
    Commented Sep 24, 2015 at 17:41
  • $\begingroup$ "Dick" was a popular nickname for "Richard" among the 50 years and older crowd in the U.S., kind of like "Chuck" (from "Charles") and "Betsy" (from "Elizabeth"). $\endgroup$
    – Roland
    Commented Sep 24, 2015 at 18:27
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Hmm this isn't used commonly as a first name but...

It looks like an unknown object on top of something. So the question to be asked is "What's on?". Take away the 'h' and you've got WATSON

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  • $\begingroup$ Well done. I feel like the others I was close to, but I never would have gotten this. $\endgroup$
    – user1717828
    Commented Sep 25, 2015 at 1:37
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For 1, I think that:

It's a net "catching" a butterfly so the action is "catch" and the friend's name is "Cath"

For 5 I wonder if:

The friend's name is Meg - from "Mega" (Million). I have no sensible logic to explain why the action is a "Million" though, so probably wrong.

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    $\begingroup$ #5 Left cube is 10X10X10 so 1000. Each subcube expands to the right cube which also is 1000. And no, there is no further subdivision. 1000X1000=million, so your hunch seems correct. $\endgroup$
    – Klas Lindbäck
    Commented Sep 24, 2015 at 14:22
  • $\begingroup$ Nice explanation @KlasLindbäck - before you said that the meaning of the "no" had got me stumped $\endgroup$
    – jcdude
    Commented Sep 24, 2015 at 15:38
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    $\begingroup$ Or it's mega-No, which is "Megan" when you lose the "o". $\endgroup$
    – f''
    Commented Sep 24, 2015 at 17:33
  • $\begingroup$ I have a slight feeling that f'' is correct $\endgroup$
    – MathET
    Commented Sep 24, 2015 at 17:55
  • $\begingroup$ It must be very inconvenient to catch butterflies with a net like this, though $\endgroup$
    – MathET
    Commented Sep 24, 2015 at 18:04
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My guess for 5 is

Nom, because one millionth is prefixed by mu, so "No mu" becomes Nom.

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  • $\begingroup$ You are using the correct reasoning, just the other way around. Take a look at my new clue about #5 $\endgroup$
    – MathET
    Commented Sep 24, 2015 at 13:03
  • $\begingroup$ Though currently it is #6 $\endgroup$
    – MathET
    Commented Sep 24, 2015 at 23:19
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for the new friend number 1 I'm thinking,

Bo, it looks like a box to me and drop the x you get Bo which is a usual name here in the south.

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  • $\begingroup$ Not anymore, though :) $\endgroup$
    – MathET
    Commented Sep 24, 2015 at 23:15
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The rounded corners on #1 make it look a bit like

a television

So perhaps the name is

Elly (i.e., "telly" without the "t")?

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  • $\begingroup$ All right, I edited the box shape so it's not misleading people by association with common everyday things $\endgroup$
    – MathET
    Commented Sep 24, 2015 at 20:30
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Is 5...

Maximillian? It's the opposite ("no") of "mini millionth".

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  • $\begingroup$ Good catch about the "million", but this puzzle does not require you to change letters, only delete them. "Maximillian" changes the "o" in million to an "a". $\endgroup$
    – MathET
    Commented Sep 24, 2015 at 12:57
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Joining the 'million' train of thought. Is the answer to number 5:

Milli?

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1
  • $\begingroup$ Milli is two letters shorter, you are allowed to remove only one $\endgroup$
    – MathET
    Commented Sep 24, 2015 at 18:06

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