8
$\begingroup$

Alice loves magic squares. She has a 4x4 square, where she can put a number in each cell. But alas! Some evil person has poked a hole in her square. Alice is really really sad because she can't make a magic square anymore. Won't you cheer poor Alice up?

You are given a 4x4 square with 1 of its cells removed. Put the numbers 1 to 15 in it so that each row, column and diagonal sum to the same.

$\endgroup$
13
$\begingroup$

Here are a few from this site. Any magic square with integers 0-15 will work, considering the 0 as a hole. I've chosen four with the 0 in the inner four cells just to be sure it meets your criteria. The rows, columns, and diagonals of each add up to 30.

enter image description here

$\endgroup$
  • 9
    $\begingroup$ The square can be constructed by making a normal 4x4 1-16 square and subtracting 1 from each cell. $\endgroup$ – jingyu9575 Sep 16 '15 at 3:53
  • $\begingroup$ Actually it can be done even if the hole (ie. 0) is in a corner or a side as well. $\endgroup$ – Rohcana Sep 16 '15 at 5:02
  • $\begingroup$ Building on @jingyu9575 his suggestion, you can extend the idea behind it up to (and maybe beyond) a 16x16 (puzzling.stackexchange.com/questions/6250/…) , just reduce each of the numbers by one. $\endgroup$ – Tim Couwelier Sep 16 '15 at 8:40

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.