5, 11, 17, 23, 29, 41
Please note that I don't have an answer to this problem.
I thought of 2 possible answers,
a) 5 - it is the only single digit number in the sequence.
b) 41 - all other adjacent numbers have a difference of 6
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Please note that I don't have an answer to this problem.
I thought of 2 possible answers,
a) 5 - it is the only single digit number in the sequence.
b) 41 - all other adjacent numbers have a difference of 6
29 is the odd number out because
they're listing every other prime number starting from 5 (prime numbers from 5 to 41 are 5,7,11,13,17,19,23,29,31,37,41) so the sequence should have been 5,11,17,23,31,41 . 29 breaks that sequence.
5, 11, 17, 23, 29, 41
5 is the answer because
it's the only single digit number.
11 is the answer because
it contains repeating digits, which stands out amongst those numbers.
17 is the answer because
the difference between its digits is the same difference between it and the other numbers around it.
23 is the answer because
its digits are neighbors on the number line.
29 is the answer because
it has the greatest difference between its digits.
41 is the answer because
it is 12 units away from its previous neighbor in the list, rather than 6 like the others (or 5 like the first).
As you can see, each and every answer is the only true answer.
New answer
When you add up the digits in each number you get:
5, 2, 8, 5, 11, 5
all of these are prime numbers except 8 (1+7), so 17 is standing out the most
Previous answer I agree with b) 41, with a slightly different reason: all numbers are a multiple of 6 followed by minus 1, (5=6-1, 11=12-1, 17=18-1 etc)
Your original answer would never allow the first number to be out of sequence.