The question reads: From the given pattern, What comes in place of '?'

enter image description here


2 Answers 2


The answer is


It looks like:

0. Triangle from 4 figures rotates in the square anti-clockwise.
1. "S" goes around anti-clockwise, from one corner to another corner.
2. "Square" goes along main diagonal (from TopLeft to BottomRight and back).
3. "Triangle" goes along second diagonal (from TopRight to BottomLeft and back).
4. Other figures appear to chosen randomly. May be there is some pattern I do not see, but it doesn't matter, since 2 and 4 leaves us with only one possible answer, which perfectly agrees with all 5 patterns.

  • $\begingroup$ 3 is not a distinguishing feature for the answers, because all answers have the square in the center. A distinguishing feature would be that all squares contain figures at most once. That and your 2 are sufficient to justify the answer (4). $\endgroup$
    – Rhymoid
    Jun 29, 2014 at 14:37
  • $\begingroup$ @Rhymoid, I agree on the distinguish point. I fixed it. About justification point - it is enough to mention that all figures has triangle and S signs to chose between given 4 options, but any number of patterns are not enough to fully justify any answer, induction can not be justified. Therefore it is better to have as many as possible patterns. $\endgroup$
    – klm123
    Jun 29, 2014 at 14:43
  • $\begingroup$ That's the difference between constructing answers and eliminating non-answers. Which one is better is definitely up for debate, seeing how different schools in (formal) logic are divided over a similar issue. $\endgroup$
    – Rhymoid
    Jun 29, 2014 at 17:57
  • $\begingroup$ (3) isn't a discriminating feature, but it gives weight to (4). $\endgroup$
    – Florian F
    Nov 26, 2014 at 22:47

I also answer (4) but I'd like to define the reason in another way.

It appears to be a control structure in the patter, formed by: a 'triangle', a 'square' and a 'S'.

This 3 signs form a triangle where:

  • 'S' is in a corner and rotates anti-clockwise,
  • the central vertex is 'square' or 'triangle', alternating,
  • the third vertex of the triangle-structure is occupied by the remaining sign.

Figure number (4) is the only one validated by this pattern. (1) and (3) don't show a 'S' and in particular the (1)'s 'triangle' is not where it were supposed to be. (2) shows two 'squares' and no 'triangle', quite strange.

  • $\begingroup$ Keeping the 'S' criterion, and noting that the triangle cycles along the rising diagonal also limits candidates to number (4). $\endgroup$
    – user2837
    Oct 10, 2014 at 13:44

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.