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Can you decipher the numbers and determine who I am?

24083272403040832724032608240304120727327240824071232724082308

This is my first puzzle and I have no idea how hard this is going to be, but I'd love some feedback

Hint 1:

Groups of twos and threes are key

Hint 2:

I'm not your standard person, I'm a little quirky

Hint 3: (Warning this is a major spoiler)

Rows, Cols

Hint 4: (Since no one has figured it out, this is the biggest hint by far)

Keyboards are laid out like a grid

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    $\begingroup$ Typically puzzles like this with just a string of numbers and no hints or clues are poorly received on PSE. If you truly think this will be solvable without any hints, you can leave it as-is, but you'll likely get more positive feedback if you at least point us in the right direction! $\endgroup$
    – Bailey M
    Commented Jul 14, 2015 at 20:48
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    $\begingroup$ This puzzle is not a good example of a question we'd like to see on this site. For more information please see this meta question: meta.puzzling.stackexchange.com/questions/1717/… So I, voted to close as Too Broad (surprised nobody else did) $\endgroup$
    – warspyking
    Commented Jul 14, 2015 at 21:40
  • $\begingroup$ @BaileyM I added a hint. I hope that helps point everyone in the right direction. I think it's solvable from there $\endgroup$
    – SirParselot
    Commented Jul 15, 2015 at 13:13

3 Answers 3

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You are

Dr. John Faust from V for Vendetta

Using the list from @AlirezaTabatabaeian and the last clue

Each row of letters on your keyboard is numbered 0-3 and each column is numbered starting at 1. Taking each number pair as a Row/Column and 327 being a space as it is in the 3rd row and extends from col 2 to col 7 (from @BaileyM) gives you "Vi Veri Veniversum Vivus Vici" - a quote attributed to Dr. John Faust in the movie V for Vendetta.

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  • $\begingroup$ Spaces are '327' because they're in the 3rd row and extend from col 2 to col 7. :P $\endgroup$
    – Bailey M
    Commented Aug 4, 2015 at 19:50
  • $\begingroup$ This same message could also lead to Aleister Crowley. $\endgroup$
    – Set Big O
    Commented Aug 4, 2015 at 20:05
  • $\begingroup$ @Geobits I did not know that phrase was in his writings, but Lampost42 was correct in his answer. Since that phrase pulls up V for Vendetta first it seems like an easy jump $\endgroup$
    – SirParselot
    Commented Aug 4, 2015 at 20:09
  • $\begingroup$ I'm glad someone finally got this even though I basically gave it away in the hints $\endgroup$
    – SirParselot
    Commented Aug 4, 2015 at 20:10
  • $\begingroup$ Right, I'm not saying he's wrong at all, just that the phrase doesn't necessarily lead to a single person, so I'd count either as right. For the record, Googling that phrase brings up this wiki page as the first result for me, where it shows both sources. $\endgroup$
    – Set Big O
    Commented Aug 4, 2015 at 20:12
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24 08 327

24 03 04 08 327

24 03 26 08

24 03 04 12 07 27 327

24 08 24 07 12 327

24 08 23 08

looks like a patern all lines starts with 24 and end up to 327 or 08

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    $\begingroup$ This is actually pretty good. Each of your lines could be a word, with each group of digits corresponding to a letter. $\endgroup$
    – Rand al'Thor
    Commented Jul 15, 2015 at 15:11
  • $\begingroup$ @randal'thor is on the right track $\endgroup$
    – SirParselot
    Commented Jul 15, 2015 at 19:16
  • $\begingroup$ @randal'thor I wouldn't put each set on a different line $\endgroup$
    – SirParselot
    Commented Aug 4, 2015 at 12:57
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Partial Answer

Since the hint says that "groups of twos and threes" are relevant, I hunted through the list to find some. 2408 and 327 show up multiple times. Splitting the string up such that 24, 08, and 327 are all pulled out by themselves, we get:

24 08 327 24 0304 08 327 24 0326 08 24 0304120727 327 24 08 24 0712 327 24 08 2308

If we then split the 0# strings up as sets of twos, we get the resulting string:

24 08 327 24 03 04 08 327 24 03 26 08 24 03 04 12 07 27 327 24 08 24 07 12 327 24 08 23 08

This doesn't appear to be ascii or alphabetical characters, since neither really fit the pattern. I'm a bit concerned with the 07 27 327 since that's the only location that 27 shows up exclusively from 327. From this point, I'm not sure where to go, but it's a start, at least.

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  • $\begingroup$ Not a lot of progress, but maybe looking at the split characters will give someone else inspiration to solve the rest. $\endgroup$
    – Bailey M
    Commented Jul 15, 2015 at 14:24
  • $\begingroup$ you are on the right track but you've missed part of the hint $\endgroup$
    – SirParselot
    Commented Jul 15, 2015 at 14:32

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