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Tonight I went to my friend's for a movie night and he asked me what we should watch.

As I was playful, I handed him the following picture so he could guess the movie:

enter image description here

He couldn't figure it out, so after a while I gave him the following hint:

Tolerance is not important

But he was still stuck.

Could you help him find the movie?

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    $\begingroup$ I don't like riddles which require obscure domain knowledge like this. $\endgroup$
    – Philipp
    Jun 16, 2015 at 7:22
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    $\begingroup$ @Philipp, Questions like these can be hard to resist $\endgroup$
    – Mark N
    Jun 16, 2015 at 14:16
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    $\begingroup$ Had you seen Tryth's very similar puzzle when you posted this? I haven't studied either of them closely enough to tell whether this should be closed as a duplicate, but am just leaving this comment so others are aware of the possible issue here. $\endgroup$ Jun 16, 2015 at 14:48
  • $\begingroup$ @randal'thor No I didn't. I was surprised that it was so similar. $\endgroup$
    – A.D.
    Jun 16, 2015 at 14:49

1 Answer 1

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The movie is:

Star Trek: First Contact (1996)

The message is:

Resistance is futile. Although this phrase was used in earlier Star Trek episodes, it was made more popular as the tagline of the 1996 film Star Trek: First Contact by the actor Jeff Coopwood who was the "Voice of the Borg".

The encoding uses:

resistor codes as shown in the following chart. Per the hint, the tolerance band is absent. The resistor codes are then converted to ASCII characters as shown below.

Resistor codes

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    $\begingroup$ Was literally typing my answer as you posted. Damn :) $\endgroup$
    – Tryth
    Jun 16, 2015 at 2:07
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    $\begingroup$ Beat me by about 30 sec.. I know I've seen this before though. $\endgroup$
    – Quark
    Jun 16, 2015 at 2:08
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    $\begingroup$ @Quark Maybe because I had a very similar idea before :p $\endgroup$
    – Tryth
    Jun 16, 2015 at 2:09
  • $\begingroup$ @Tryth ah that was it. Funny how although it wasn't space related, the message also matched (either coincidence or homage probably). $\endgroup$
    – Quark
    Jun 16, 2015 at 2:10
  • $\begingroup$ @Len that answer is right though... not sure how another would benefit. $\endgroup$
    – Quark
    Jun 16, 2015 at 2:15

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