You are trying to crack someone's password. You don't have any password cracking software, nor do you have time to get any. From sources unknown, you know that:

A. The password is alphanumeric (only letters and numbers)

B. It's length is between 6 and 10

C. 25% of all the characters are numbers

D. The password is case insensitive

E. All the digits are at the end of the password (after the letters)

F. The first letter of the password is J

G. The sum of the digits are equal to the numerical value of the first letter

H. There is one E, one U and one Z in the password inclusively (they appear in that order)

I. The first digit is equal to the numerical value of the second letter

J. The product of all the digits is equal to the last letter

K. The letter that was unmentioned (not declared) is d upside down and mirrored.

L. The numerical difference between the third letter and the Z is more than 6

• @JLee Checked it just now, yes that is right. – bitbyte Jun 14 '15 at 15:50
• Should condition I be "The first digit is equal to the numerical value of the second character/letter"? – Julian Rosen Jun 14 '15 at 15:50
• @Julian Ronsen The second character is a letter, from condition E, All the digits are at the end of the password (after the letters). – bitbyte Jun 14 '15 at 15:54
• Since the second character is not a number, maybe this should say "the numerical value of the second letter" instead of "the numerical value of the second number" – Julian Rosen Jun 14 '15 at 15:59
• @BitCoder rule K may be ambiguous, when you flip something upside down you can either rotate it 180 degrees or flip over its horizontal axis. Another possible interpretation is that "upside down and mirrored" both refer to the same transformation (e.g. q). Is this solvable as is or should it be clarified? – Quark Jun 14 '15 at 16:15

JEQUZY55. 25% of the password are numbers, and the only number between 6 and 10 that can be broken up this way is 8. Therefore there are 6 letters and 2 numbers. The 6 letters include J,E,U,Z, and Q so far. One of these must be the first of these two digits which make the first digit 5. The sum of these digits is 10 making both digits 5, making the product 25. This makes the last letter Y. The letters JEUZY are in order, and Q can be anywhere between the E (Rule I) and the Y. For Rule L, the third letter can't be U, meaning it is Q.

• That is correct! Good job :) – bitbyte Jun 14 '15 at 16:30
• To the edit, rule D says the password is case insensitive but I guess it doesn't really matter either way. – Quark May 21 '16 at 20:27
• @JorVa I hit the rollback as the post explicitly stated that the password is case INsensitive. Perhaps a comment would serve better here -- just mention that's where the logic comes in for that particular rule (K). – feelinferrety May 24 '16 at 0:08