# Someone has vandalised this long division. Can you reconstruct it?

Oh dear, someone has vandalised this long division.

They've replaced every digit either with a wrong digit or a hyphen.

Please show all work. Use of a computer is not allowed. • Wow. So just to confirm, none of the digits that are in the puzzle are correct? – LeppyR64 Jun 14 '15 at 0:31
• Are there multiple answers to this? – Quark Jun 14 '15 at 0:37
• @LeppyR64 thanks for mentioning that. I missed the wrong digit part and was wondering what this was all about. – Bob Jun 14 '15 at 0:38
• Quark and JLee - There's only one correct answer. Leppy - Yes. – h34 Jun 14 '15 at 0:43
• This is a cool question. – LeppyR64 Jun 14 '15 at 0:50 In the second subtraction, the number being subtracted is three digits, and the first digit isn't 1. So it must be at least 200, and the divisor is at least 21. Since the first digit of the divisor isn't 2, the divisor must be at least 30.

In the first subtraction, the number being subtracted is at least twice the divisor, but is only two digits. So the divisor is at most 49.

At the end, there is a two digit number, where the first digit is not 9. It is at most 89. This means that the last digit of the quotient cannot be 3 or more, so it must be 1. Then the divisor cannot start with 3, so it is 40-49.

The first digit of the quotient must be 2. Twice the divisor cannot start with 8, so the divisor is 45-49. The last digit of the divisor is not 5, 6, 8, or 9, so the divisor is 47.

The second digit of the quotient must be at least 5, because 4*47 is less than 200. But it can't be 5 because the 5 is wrong, it can't be 7 (7*47=329) or 9 (9*47=423) because the 2 is wrong, and it can't be 6. So it is 8.

Now the third digit of the quotient is the only one missing. It can't be 1 or 2 because those are too small. It can't be 3 because the 4 is wrong, it can't be 4 because the 8 is wrong, and it can't be 5 or 6 because the 2 is wrong. It also can't be 7 or 8 because the 3 on the preceding line is wrong, and the numbers subtract to only 4. So the missing digit is 9.

The complete division is 135877/47=2891. The subtractions are 135-94, 418-376, 427-423, and 47-47.

• This is the right answer. Nicely done! :-) – h34 Jun 14 '15 at 12:57
• Well done. Here's a pic. (I can't seem to make it display here in the comment.) – r.e.s. Jun 14 '15 at 13:25

I think I found the answer.

Step one to find the divisor.

By looking at the number we know that the first three digits of dividend is quite close to 100 because the divisor is dividing it with 2 digits. And second things is the reminder of the first division is smaller than divisor and thats why the number has to be between 21-25. I thought odd number has more possibility to get this answer.

I started with

25 as divisor but it is hard to get 2 digit reminder in second step of division. Then I tried 23.

Now this number start making sense in my mind. Here's how

23x4 =92 which is very close to 100 and 23x5=115 which more quiet far from 100. so i chose 113 number between 100 and 115 Now if you divide 113 with 23 you will get 21 as remainder. Now according to given division it has to be small than divisor because we are going to drop one more number from dividend. Now that Number has to be close to a number which is close divisible by 23 and get 2 digit number as remainder which is also has to be smaller than 23.

Second step of division.

So far we have first three digits of dividend 113 and 21 as remainder and now we are going to decide the fourth digit of dividend. I started with number 9 because its the biggest single digit number. so now we got number 1139 and our remainder become 219.Now 23 x 9 =207 which is the closest to 219. so now we got two digit remainder 12 which is smaller that 23.

Third step of division.

So far we got first four digits of dividend which is 1139 and quotient 49. Now its time to find fifth digit of dividend. lets say the smallest number we can use is 0 which makes remainder as 120 and when you divide it with 23 you will get 5 as remainder and there is no two digit number which start with 5 is divisible by 23. so I change that fifth number to 1. Now remainder become 121 and when you divide 121 with 23 you will get 6 as remainder.

Fourth/Final step of division

Now we have first five digits of dividend which are 11391 and first three digits of quotient which are 495. We have 6 as a remainder and there is one number which start with 6 and also divisible by 23 and that is 69. ;-) (23 x 3=69) So our last digit of dividend is 9. and our last digit of quotient is 3.

Here is my actual work  