Here is my puzzle:
How can you fit ten horses in nine boxes?
Here are the boxes:
Rules:
- All boxes must be filled
- No additional boxes can be created
Good luck :)
$\begingroup$
$\endgroup$
-
$\begingroup$ Does one box can only contains one horse? $\endgroup$ – TroyAndAbed Jun 1 '15 at 13:22
-
$\begingroup$ That's what I was about to ask $\endgroup$ – the4seasons Jun 1 '15 at 13:24
-
5$\begingroup$ Somewhat relevant: xkcd.com/169 $\endgroup$ – Engineer Toast Jun 1 '15 at 13:30
-
$\begingroup$ @NSPredator Should all the horses be alive? $\endgroup$ – kanchirk Jun 1 '15 at 14:04
-
$\begingroup$ Easy, you chop one of the horses into 9 equal pieces and put one-and-a-ninth horses in each box. $\endgroup$ – A E Jun 3 '15 at 15:26
$\begingroup$
$\endgroup$
Put 8 male horses to first 8 box and put a pregnant female horse to last room.
-
$\begingroup$ This would be a fantastic answer if the question had the 'lateral-thinking' tab! $\endgroup$ – Bailey M Jun 1 '15 at 13:58
-
$\begingroup$ @shyos why not 9 pregnant horses and say you have put 18 horses in 9 boxes. ;-) $\endgroup$ – kanchirk Jun 1 '15 at 14:02
-
$\begingroup$ why not 36, and all 9 are having triplets? :) (although, after googling, it is so rare that triplet births in horses have never once been known to result in 3 surviving babies, and twins is also rare and usually ends in deaths) $\endgroup$ – JLee Jun 1 '15 at 14:13
-
$\begingroup$ @JLee well, there is no ruls on the question indicates that horses cant be dead, still counts :) $\endgroup$ – shyos Jun 1 '15 at 15:31
$\begingroup$
$\endgroup$
Here is my answer:
You can place the 9 letters of "ten horses" in the boxes: T E N H O R S E S
$\begingroup$
$\endgroup$
Obviously, this. I can't think anything else really.
$\begingroup$
$\endgroup$
The expected answer:
|1 | 2 |3 | 4 | 5 |6 | 7 |8 | 9 |
[T][E][N][H][O][R][S][E][S]
Now the real challenge is to make up new valid answers..
Alternate answers:
Remove the walls between the boxes to and add them to the end to end up with just 1 longer box, then insert all the horses into the 1 box. (Can now store up to 10-13 horses!)
Assuming they are toy horses, and grind them up. You can now fit the maximum possible horses into the boxes. (Much greater than 10)
$\begingroup$
$\endgroup$
My idea:
If you order the boxes like this:
+---+---+---+---+ | 1 | 2 | 3 | 4 | +---+---+---+---+ | 5 | | 6 | +---+---+---+---+ | 7 | 8 | 9 |//// +---+---+---+////you get a spot in the middle that is no box but yet big enough for the tenth horse, and you can get to it by moving box 6 to the shaded zone.
$\begingroup$
$\endgroup$
You can double up one of the boxes because these 9 boxes make up the bigger box (box of boxes). You didn't say only 1 horse per box.
