5
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I found this puzzle in a school study group. Choices are 9, 10,11, 12, 13.

$$ \begin{array}{|c|c|c|c|} \hline 22& 22 & 23 & 24 \\ \hline 22 & 32& 41& 52\\ \hline 23 & 41 & 50 & 61\\ \hline x & 17 & 26& 37 \\ \hline \end{array} $$

I have tried so many operations on these numbers with many various arrangements.

I think the 4th row is a result of first three rows.

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3
  • $\begingroup$ Where did you get this puzzle from? $\endgroup$
    – Someone
    Apr 18 at 17:02
  • $\begingroup$ If you got it through school, is it homework? Some sort of contest for students? $\endgroup$
    – bobble
    Apr 18 at 17:57
  • $\begingroup$ No its not a homework or contest question. Its just a practice question, but it is really hard and I have been stuck with it for a week. $\endgroup$
    – Gablin32
    Apr 18 at 18:00

1 Answer 1

5
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The answer is

9

Logic

Column wise the number in the bottom row is the result of sum of red x orange + sum of yellow - green enter image description here So for the first column you get: (2+2)x2+(2+2-3)=9

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2
  • $\begingroup$ And with that I am off to bed. $\endgroup$
    – PDT
    Apr 18 at 18:26
  • 1
    $\begingroup$ Unbelievable solution. $\endgroup$
    – Gablin32
    Apr 18 at 19:10

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