How to get the numbers from 50 - 100 with the numbers 2, 0, 2, 4

Question

All I need is 56-59, 69, 73, 75- 77, 79, 86, 90-94, 99. I've done the rest but I would love to hear other solutions.

Rules:

1. Use any of the following operations: basic operations (+ - x /), to the power of (^), Square root, factorial, double factorial, concatenation (e.g. 42 is acceptable).
2. You can write the numbers in any order but you may only use each number once.

Good Luck!

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In a comment, the OP said, “Repeating decimals are not allowed as an answer (e.g. 92.22222 ≠ 92). But you may use repeating decimals as part of an equation (don't know any case).”

Answer 1

Work in progress

$58 = (4+0!)! / 2 - 2$
$59 = ((4+0!)! - 2) / 2$
$86 = (42 + 0!) \times 2$
$94 = ((4 + 2)!! - 0! ) \times 2$

Answer 2

Partial Answer:

$56 = ((2 + 0!)!)!! + 2 \times 4$
$58 = ((2 + 0!)!)!! + 4!! + 2$ or $(4!!)^2 - (2 + 0!)!$
$69 = \frac{0!}{.\bar{2} - .2} + 4! $
$79 = (4!! + 0!)^2 - 2$ or $79 = (2 + 0!)^4 - 2$
$90 = 42 + ((2 + 0!)!)!!$
$99 = (4!! + 2)^2 - 0!$

Answer 3

Partial answer:

$\large 57=((2+0!)!)!!+\frac{\sqrt{4}}{.\bar2}$

$\large 69=((4!)-(0!)) \times \sqrt{ \frac{2}{.\bar2} }$

$\large 71=4! \times \sqrt{\frac{2}{.\bar2}} -0!$

$\large 73=4! \times \sqrt{\frac{2}{.\bar2}} +0!$

$\large 75=((4!)+(0!)) \times \sqrt{ \frac{2}{.\bar2} }$

$\large 76=2 \times (40-2)$

$\large 91=\frac{\sqrt{4}}{.\bar2-.2} + 0!$

Answer 4

Someone mentioned only 77 and 93 were remaining.

Here is 77:

$77 = ((4!!)!!)*.2 + .2 + 0$
or
$77 = (((4!!)!!) + 2 - 0!) * .2$

And here is 93:

$93 = \frac{4!}{.\bar2} - (\frac{0!}{.2})!!$