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I made this challenge.

Later this decade, Amelia and Jack operates a restaurant where they serve a lot of tasty meals and delicious product. Recently, their income from the restaurant is triple more than the past couple days because the restaurant is now open for whole day in a week. They know that this is result of a power of effort.

Because of that, they inquired a events manager and the couple said that the wedding date is one day before weekend.

They write the date as this:

$YYYY/DD/MM$, where $y$ is a four digit number, $dd$ is any digit from $1-31$(leading zeroes are allowed, example: $01$), $M$ is any month from January to September.

Their wedding time is scheduled to start at a week before the midnight of weekend and dozens of egg their ordered delivered after a few minutes.

So the wedding time is like this:

$hh:mm$, where $hh$ is hour and $mm$ is minutes.

When is the wedding day, what is the day of their wedding day and what time is start of their wedding?

Hint:

  • the year is between the 4th and 10th year of a decade and the year is any year in the current century.
  • Couple is raised to the product of week and triple.
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  • $\begingroup$ we'll need some more hints here, I think.. :) "product = triple week to the power of couple", does this refer to (3x7)^2 ? $\endgroup$ Jan 4 at 12:48

1 Answer 1

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The date is

2097/15/02

because

Couple (2) raised to the product of triple week = 2^(3*7) = 2097152

As specified by "said that the wedding date is one day before weekend", this date is a friday

I think (not entirely sure) that the time is

17:12

because

"a week before midnight" = 24-7 = 17
"and dozens minutes" = 12

Alternatively we could ignore "midnight" because it is not marked bold and end up with 7:12

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    $\begingroup$ How do you get 10 from dozens? $\endgroup$
    – fljx
    Jan 5 at 13:33
  • $\begingroup$ @fljx good question :) fixed now $\endgroup$ Jan 5 at 14:02
  • $\begingroup$ Given that "dozens" is plural, I'd have made that 24 instead of 12. $\endgroup$ Jan 5 at 14:37

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