# PSE Advent Calendar 2023 (Day 18): A holly jolly Hexologic

This puzzle is part of the Puzzling Stack Exchange Advent Calendar 2023. The accepted answer to this question will be awarded a bounty worth 50 reputation.

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Rules:

Normal Hexologic rules apply

• You can place one, two or three dots in each blank space.
• The number value of the cells in a given row must add up to the number that is pointing towards that row.
• If you put a number in a colored cell, then all cells that are colored the same color also have that number.
• Numbers that are greater than 3 that are already on the grid are forced numbers that are already part of the puzzle.

#### Desmos link for partially colorblind puzzlers

For partially colorblind puzzlers (hue is changed from 0.4 to 0.7)

{1}only thing that I found that would let me place proper hexagons tbh

• I hate to say it, but there aren't any arrows in the image.
– fljx
Dec 18, 2023 at 18:10
• @fljx sorry about that, I was for some reason unable to make that work. I've been attempting to fix it on a copy but am unable to for some reason Dec 18, 2023 at 18:11
• It's fairly clear which rows the numbers should be pointing at. But your instructions mention arrows.
– fljx
Dec 18, 2023 at 18:17
• I don't think this is solvable as-is. The down-left 13 requires 8 from 3 unknown cells, which must be 2,3,3 in some order. But the 3 in the second column from the left requires all 1's.
– fljx
Dec 18, 2023 at 18:36
• "If you put a number in a colored cell, then all cells that are colored the same color also have that number. Numbers that are greater than 3 that are already on the grid are forced numbers that are already part of the puzzle." That'd imply all already-numbered cells of the same color have the same number. They don't. Dec 18, 2023 at 19:05

The completed tree:

The solve path:

• The 6 column on the left must have a 3 in both cells.
• And the adjacent 3 column must have a 1 in every cell.
• That makes all the green cells 1.
• The down-left 20 now needs another 6 from two cells, so both must be 3.
• And that makes all the red cells 3.
• And the down-right 10 has one unknown cell that must be a 3.

• The 5 column on the right has one unknown cell that must be a 2.
• The down-left 9 has one unknown cell that must be a 2.
• That makes all the blue cells 2.
• And now the up-left 10 has one unknown cell that must be 1.
• And the down-left 12 has one unknown cell that must be 2.

• The up-right 9 has one unknown cell that must be 3.
• And now the big 27 column has one unknown cell that must be 2.
• The 11 column has one unknown cell that must be 3.
• And finally, the last empty cell must be 1 to complete the down-right 12.