Use the numbers 8,6,4,2 and the operators +,-,*,/ to get 25.

You can use each number once.

Each operator can be used once.

The least number of operators you use the better answer will be.

  • 1
    $\begingroup$ mabye you want to add the no computer tag, since many people have written a bit of code to get 100 or 1 with the numbers 0-9 and those operators so it will be trivial to do this. Also, maybe add the condition: "with the least number of operators" because this will probably have multiple solutions $\endgroup$
    – Vincent
    Apr 17 '15 at 11:37
  • $\begingroup$ @VincentAdvocaat thanks for your notes $\endgroup$
    – Maythux
    Apr 17 '15 at 11:39
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    $\begingroup$ may be 4*(6+(2/8)) $\endgroup$ Apr 17 '15 at 11:46
  • $\begingroup$ @SaurabhPrajapati Put that in an answer instead of a comment $\endgroup$
    – Lopsy
    Apr 17 '15 at 11:47
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    $\begingroup$ We have 4 numbers, 4 operators. All those operators need 2 arguments. One of the operators isn't used? $\endgroup$
    – leoll2
    Apr 17 '15 at 11:50

Answer of this question is



here is my solution, just with 2 operators:

(98+2)/4=25, where 6 is upside down

  • $\begingroup$ This would be a good answer if there was a "lateral thinking" tag but these kinds of answers can get overwelming on questions that don't have that element. Still entertaining answer this time though. $\endgroup$
    – kaine
    Apr 17 '15 at 20:30
  • $\begingroup$ If this answer is valid, so is 29-4. $\endgroup$ Nov 12 '18 at 5:21

They are all even numbers. No matter what u do the answer has to be an even number. It could be (8*6+4)/2=26 etc

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    $\begingroup$ Puzzling.SE is a bit different from other StackExchange sites, but we're still a question and answer site. Please read the existing answers before posting your own. You aren't improving the quality of the site by posting that a question can't be answered 3.5 years after an answer has been posted and accepted. $\endgroup$ Nov 12 '18 at 2:10
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    $\begingroup$ division leads out from the territory of even numbers, just think about 6/2 or using all the digits (8*4+6)/2 for example $\endgroup$
    – elias
    Nov 12 '18 at 8:32

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