Grid 1:

Grid 1

Grid 2:

Grid 2

Grid 3:

Grid 3

Find the meaning behind these images.

Hint 1:

The puzzle involves three-dimensional Euclidean space.

Hint 2:


Hint 3:


  • $\begingroup$ I have an idea, but it's related to something that definitely requires the knowledge-tag in order to solve it but since you added the knowledge-tag later, I'm not so sure... $\endgroup$ Oct 3, 2023 at 11:50
  • $\begingroup$ @Prim3numbah It's worth a shot; the knowledge tag is there, isn't it? $\endgroup$ Oct 3, 2023 at 12:12
  • $\begingroup$ @BlueHerring Yes, but since it says "may be relevant" in the description of the edit I'm not that sure. I might post a rot13 comment later, to see if I'm on the right track or completely off. $\endgroup$ Oct 3, 2023 at 12:22
  • $\begingroup$ @Prim3numbah - I'm not sure if the puzzle needs "knowledge" tag myself. It doesn't provide everything needed to solve it itself, so some outside knowledge is required. $\endgroup$ Oct 3, 2023 at 12:58
  • $\begingroup$ Does it have anything to do with rot13(fgnef/pbafgryyngvbaf) or is this completely off? $\endgroup$ Oct 9, 2023 at 10:52

1 Answer 1


The answer is:

Each of the rows on each grid represent a set of 3D coordinates except for the bottom row of the third grid. The empty squares represent zeros and the squares with a horizontal line represents 1. From left to right it is the (x,y,z) coordinates respectively. The result is that in three-dimensional Euclidean space the 8 set of coordinates map out the vertices of a cube like so:

enter image description here

The significance of 27

Is the fact that it is a perfect cube number!

  • $\begingroup$ This answer is correct, but there is a remarkable detail here. If one were to draw a cube in three-dimensional Euclidean space with the side length of 2 and centered on 0, then all its vertices would be on either +/- 1 x/y/z. Cells with no strokes would contain +1, cells with strokes would contain -1. $\endgroup$ Jan 23 at 0:31
  • $\begingroup$ Sorry did I miss something that I should add in my answer?? $\endgroup$
    – PDT
    Jan 23 at 12:56
  • $\begingroup$ No, your answer is not wrong, I accept it. I was just expecting a different answer. Now I see yours is also valid. In a nutshell, if you put 1s in all cells except those with diagonal strokes, they will be coordinates of a cube centered on 0 with side length of 2. Cells with horizontal strokes will have -1s. $\endgroup$ Jan 23 at 14:38

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