This puzzle is part of the Monthly Topic Challenge #13: Variety Slitherlinks.

Rules of hexagonal Slitherlink:

  • Draw one continuous loop in the grid along dotted lines. The line cannot cross itself or branch out.
  • Numbers in cells give how many of the cell's six sides is filled as part of the loop.

Solve on Penpa+

Empty hexagonal Slitherlink grid

  • $\begingroup$ I really enjoy these kinds of deduction games (I've beaten CrossCells, SquareCells, HexCells/Plus/Infinite, Tametsi) but I'm feeling completely lost on this one. Is there a more simple tutorial that introduces this style of deduction? I feel like I'm completely missing the patterns here. $\endgroup$ Commented Aug 3, 2023 at 18:14
  • $\begingroup$ Also: On Penpa+ is there some better way to reset the board? "delete all" doesn't fix it, nor does a page refresh, nor does clearing cache. $\endgroup$ Commented Aug 3, 2023 at 18:21

2 Answers 2


A lot of fun!

Solution from penpa

Not sure how much I can recreate of the solving process, but

start with the two adjacent 5-cells the edge between them must be filled and the two absent edges have to be adjacent to the shared edge. Further the 4 cell above must have the upper 2 edges filled.

Then note

Every unfinished edge has only two options for how to extend and no vertex can have three edges coming in.

  • 1
    $\begingroup$ The "2" in the 4th row from the top (kind of under and to the right of the "4") has three sides with a line on it $\endgroup$
    – El Guapo
    Commented Aug 2, 2023 at 21:45
  • $\begingroup$ @ElGuapo <buries head in shame> Call it a typo? Corrected version now added (three edges changed) $\endgroup$
    – Daniel S
    Commented Aug 3, 2023 at 5:44

The final grid looks like this:

enter image description here

I can provide a detailed solve path if required, but it was all basic deductions.
Curiously, I got the congratulations message from Penpa before I had a complete loop.

  • 2
    $\begingroup$ Argh, I must have had the "ignore lines on grid borders" option on, which explains the early message. Sorry about that! $\endgroup$
    – Jafe
    Commented Aug 3, 2023 at 8:01

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