Given the queen excluder constraint, this position is
Let's assume this position can be reached
White's original queen can't get over the excluder line, therefore white must have promoted a pawn to get a queen over the line.
Counting the pieces on the board, we can see that both black and white are missing a pawn, and no other pieces. Since no move in chess can add pieces to the board, we >! can deduce there has been exactly one capture by both sides.
White's missing pawn must be the queen on f7 after promoting, so black must have taken white's original queen. We can see black has doubled d pawns, and doubled pawns in chess can only happen after a capture, therefore black's capture must have been the move e5 x Qd4.
From this we can deduce that white must have promoted his d pawn, since black hasn't taken it, and it is off the board. For white's d pawn to promote, it must have taken at least once, since the path to d8 is blocked by a black pawn. Meaning white's d pawn must have taken on the e file, and promoted on e8.
We know white has taken a black pawn as its only capture, and black's pawn that could have been captured are the e and f pawns. But we already determined black's e pawn reaches d4, therefore white has taken black's f pawn.
For this position to be reached, white's d pawn must have taken black's f pawn, but since they are more than 1 file apart, this is impossible, hence the position is unreachable.
If white promotes on e8 after black takes its queen on d4, white's d pawn must end up on e4, which means capturing either on e3 or on e4. Black's only piece that can be captured is the f pawn, and it can't change file since black has no captures except on d4, white's d pawn can't reach e4.