19
$\begingroup$

I created this puzzle for an escape room type game. You find these 12 monster cards that are the clue to open a three digit combination lock:

What three digit number can you get from the cards?

$\endgroup$
1
  • $\begingroup$ I'm pretty sure I know what the numbers are (although the first two could be in either order), I just can't figure out how to r13(anghenyyl beqre gur pneqf fb gung gurl perngr gurfr ahzoref. V whfg qvq vg ol wvtfnj chmmyvat naq nz gelvat gb erirefr-ratvarre gur beqre.) $\endgroup$
    – Johnson
    May 15, 2023 at 1:46

1 Answer 1

14
$\begingroup$

The answer is :

327

How can you find it too ?

On each of the cards, some characteristics are the exact same as others. e.g. Hapharis has the same stamina as Phytix, the same intelligence as Perilos and the same size as Quorup. This creates a mesh of creatures, following the links !
Any monster that has the same value as another monster is then linked to that monster, creating a nice graph of all the monsters in a noticeable pattern. (e.g. Hapharis is now linked to Phytix, Perilos and Quorup.)

Once you did, you should obtain this :

Phytix ----- Hapharis ----- Quorup ---- Lalaris ---- Occalia ----- Bolix
| | | | | |
Megamox ----- Perilos ---- Vesperto ---- Slima --- Pertroklops --- Kugala

The order they are placed in is not arbitrary, but this leads to the final part of the puzzle !

About time to look at those pesky card corners : All cards have a grid, 2 by 3, with black & white squares. All are similar, except a special one, Kugala, who contains a key to solve the placement easily !

Thanks to the graph we already created linking all the cards with each other, we can see that it follows the same pattern as the grid, and surprise, Kugala is already in the bottom right corner ! (well, I made it that way, since I had the graph made for solving the puzzle...) This means we simply have to fill a big grid with all our 2 by 3 grids, and voila :


To help see that Kugala is a special card, it is also foiled, which is a nice touch ;)

$\endgroup$
1
  • $\begingroup$ Yes, this is absolutely right! Well done! $\endgroup$
    – formica
    May 15, 2023 at 18:20

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.