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Symsquare4: The answer is a square grid which has the same words vertically and horizontally. The clue is a single sentence written in cryptic style and includes one anagram, one hidden word, one Charade and one Double Meaning, all as syntactically separate units. A rank indicator will indicate which word the anagram is:

A bronze Swede now will show interest to nurture an article on resistance identity with a slippery tire.

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    $\begingroup$ Where is this from? $\endgroup$
    – bobble
    Feb 21 at 23:28
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    $\begingroup$ Original designed by me $\endgroup$
    – Claude Goeminne
    Feb 22 at 5:09
  • $\begingroup$ What does 'Symsquare4' mean? (Specifically the '4', since the title instead refers to '01'...) Thanks. $\endgroup$
    – Stiv
    Feb 22 at 8:49
  • $\begingroup$ the number of letters in each word that comprises the 4 word answer $\endgroup$
    – Claude Goeminne
    Feb 22 at 10:44

1 Answer 1

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Big thank you to Deusovi for clearing up the issues I had with the grid which should look like the following

 C A R E
 A R I D
 R I T E
 E D E N

Anagram

"a slippery tire"
RITE = anagram of tire

Charade

"an article on resistance identity"

"an article" = A
"resistance" = R
"identity" = ID
Overall, giving ARID

Double meaning

"show interest to nurture"
CARE can mean "show interest" or "nurture".

Hidden word

"A bronze Swede now"
EDEN is hidden inside "swEDE Now"

Original attempt for posterity

 P A T E
 A R I A
 T I E R
 E A R N

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    $\begingroup$ What you've called a "hidden word" is actually a charade; a "hidden word" is one where some substring of the clue is taken (usually spanning a gap between two words). "Swede now will show" works that way, giving EDEN, which almost works with your current grid... $\endgroup$
    – Deusovi ♦
    Feb 22 at 13:14
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    $\begingroup$ ...and that can be fixed by choosing "identity" = ID rather than I, making the last word ARID rather than ARIA. $\endgroup$
    – Deusovi ♦
    Feb 22 at 13:15
  • $\begingroup$ @Deusovi Oh my gosh, you are absolutely right! Thank you. $\endgroup$
    – hexomino
    Feb 22 at 15:30

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