8
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  • You may use up to two subtraction symbols (no negation symbols).
  • You may use up to two decimal points.
  • You will use one vinculum for division (no "/").
  • You may use concatenation of digits only, including forming numbers which have decimal points in them.
  • You may not use grouping symbols such as parentheses, brackets, or braces.
  • You may not use factorial signs.
  • You may not use square roots.
  • You may not use exponentiation.
  • You may not use logarithms.
  • You may not use trigonometric functions.
  • You may not use any other characters or operations.
  • This is in base 10. (The numbers using the ones, and 1,000 on the other side of the equals sign, are in base 10.)

Try to create six different solutions.

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3
  • $\begingroup$ To clarify are you allowed to use any 0's or exclusively the six 1's and decimals? $\endgroup$
    – gabbo1092
    Commented Jan 30, 2023 at 17:42
  • 1
    $\begingroup$ @gabbo1092 -- No zeroes may be used. You can write .1, 1.1, .11, 1.11, etc., if they would make expressions have the correct value(s). $\endgroup$ Commented Jan 30, 2023 at 18:37
  • $\begingroup$ bin-->dec(1111101000) $\endgroup$ Commented Jan 31, 2023 at 10:03

1 Answer 1

12
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Solution 1

$\frac{111-11}{.1}$

Solution 2

$\frac{111}{.111}$

Solution 3

$\frac{1}{.111-.11}$

Solution 4

$\frac{11}{.111-.1}$

Solution 5

$\frac{11-1}{.11-.1}$

Solution 6

$\frac{111-1}{.11}$

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6
  • 1
    $\begingroup$ 1) I would not consider the negative signs you used in solutions 2 and 4 to be subtraction symbols. 2) Along with the first point, and adding in solution 6, solutions 2, 4, and 6 are not of "six different solutions" in the spirit of the forms A/B = -A/(-B). $\endgroup$ Commented Jan 30, 2023 at 18:43
  • $\begingroup$ @ hexomino -- Attention! Your solutions 3 and 4 equal -1,000. $\endgroup$ Commented Jan 30, 2023 at 18:50
  • $\begingroup$ @OliveStemforn Apologies on 3 and 4, edited now. Sorry, also, my understanding of "subtraction symbol" was that negation was okay, my mistake. $\endgroup$
    – hexomino
    Commented Jan 30, 2023 at 18:56
  • $\begingroup$ hexomino, you have essentially three different solutions out of the six different solutions in your solutions 1, 3, and 5. There are still three other solutions significantly different from those that I am looking for from any contributor(s). $\endgroup$ Commented Jan 30, 2023 at 19:14
  • 4
    $\begingroup$ @OliveStemforn I've replaced 2, 4 and 6 now with something essentially different $\endgroup$
    – hexomino
    Commented Jan 30, 2023 at 19:25

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