You are in the final round of a game show with 3,999 other conteseants.
Here is the game: The host has blindfolded you at put a red, green or blue hat and red, green or blue earrings (not necessarily matching) on each of you. Then he says truthfully, "I see a blue hat and blue earrings."
Now you will each stand in a line and each of you can see everyone else's hats and earrings except yours. Each of you must then either say two colours, say one colour or pass.
A two-colour guess is correct if one is your hat colour and one is your earring colour (in any order). A one-colour guess is correct if it is either your hat colour or your earring colour. The earrings of a player match each other.
They all start with a prize pool of £80,000,000.
If someone guesses wrong, the prize pool is divided by ten, rounded down.
If someone with a blue hat or blue earrings passes, £80 is subtracted from the prize pool.
If someone with neither a blue hat nor blue earrings passes, £25 is subtracted from the prize pool.
If someone guesses only one colour, and guessess correctly, the prize pool is multiplied by 0.95, rounded down.
The game ends when the prize pool is empty or everyone guessess correctly, then the prize pool is distributed to the players.
The players know the amount of money in the prize pool at all times.
What is the strategy to maximize your expected winnings if they go in the same order each round, and every round, each player gets one turn with unknown order?