I‘m stuck on this Kakuro. Does anyone have any hints how to proceed? Thanks!

Hard Kakuro


2 Answers 2


Besides the fact that there probably is an error in the top half...

- The 2nd row from the bottom, sum 39, has 3 cells that can ony be 7,8,9. you can strike out all other 7,8,9 (red).
- The column with sum 13 at the bottom cannot have 7 on top, so it cannot have 6 in the bottom row. So the bottom row, sum 30 has 8,9 in the center, 7,6 at the ends (blue).
- This places the 7 in the 2nd-from-bottom row, sum 39 (green).

![enter image description here


At first glance:

You have an error somewhere. :-(


Look at the 44 in the 2nd column.
- The middle four numbers (green box) must be 6,7,8,9 in some order.
- So those numbers cannot appear elsewhere in the 44 (green strikethrough).
- Now the 12 in the 2nd row must be 8,4 or 9,3 (orange strikethrough).
- And the 11 in the 1st column must be 2,9 or 3,8 (orange strikethrough).
- But now there is no valid solution for the 9 in the 1st row.
- So there must be an error in the candidate numbers in this area. Partially completed Kakuro with conflict highlighted

  • $\begingroup$ Agreed. There are other options for the 14 in the fifth column. $\endgroup$ Nov 5, 2022 at 0:41

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.