I have a physical Pentomino puzzle lying around, which contains 2 F pieces, one Y piece, one T piece and one W piece. The area into which the squares are supposed to fit in is just a little under 6 units in both directions. What layout am I supposed to use here? Is the solution to rotate a specific layout?


1 Answer 1



Yes, and since 'normal' and 45 degrees will not work, you will need to be creative.


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  • $\begingroup$ If I didn't screw up my maths this should fit into a square with side length 5/2\sqrt(5)=5.59.... $\endgroup$
    – quarague
    Sep 26, 2022 at 9:13
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    $\begingroup$ It is 2sqrt5 + 1/sqrt5+ 2/sqrt5 (5.814) $\endgroup$
    – Retudin
    Sep 26, 2022 at 10:11
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    $\begingroup$ I get $\frac52 \sqrt{5} + \frac1{2\sqrt{5}} = \frac{13}{5} \sqrt{5}$ which matches Retudin's value. $\endgroup$ Sep 26, 2022 at 12:58

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