7
$\begingroup$

I have a physical Pentomino puzzle lying around, which contains 2 F pieces, one Y piece, one T piece and one W piece. The area into which the squares are supposed to fit in is just a little under 6 units in both directions. What layout am I supposed to use here? Is the solution to rotate a specific layout?

$\endgroup$

1 Answer 1

10
$\begingroup$

Hint

Yes, and since 'normal' and 45 degrees will not work, you will need to be creative.

Solution:

enter image description here

$\endgroup$
3
  • $\begingroup$ If I didn't screw up my maths this should fit into a square with side length 5/2\sqrt(5)=5.59.... $\endgroup$
    – quarague
    Sep 26, 2022 at 9:13
  • 1
    $\begingroup$ It is 2sqrt5 + 1/sqrt5+ 2/sqrt5 (5.814) $\endgroup$
    – Retudin
    Sep 26, 2022 at 10:11
  • 1
    $\begingroup$ I get $\frac52 \sqrt{5} + \frac1{2\sqrt{5}} = \frac{13}{5} \sqrt{5}$ which matches Retudin's value. $\endgroup$ Sep 26, 2022 at 12:58

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.