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I'm looking for the shortest algorithm to rotate 2 corners without rearranging any other pieces location or orientation. For example, turning the Top-Front-Right corner clockwise and the Top-Front-Left corner counter-clockwise. My current best is 13 (formerly 16) turns, but would like to learn better if someone can share it.

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  • $\begingroup$ There is a way with 14 quarter-turns. $\endgroup$
    – Florian F
    Aug 16 at 12:32
  • $\begingroup$ Great answer below from Florian cutting 2 moves off my version. However, I was hoping someone had a way that would solve both corners at once rather than a doing one and reversing out to do the other. It there such an answer? $\endgroup$
    – JHB
    Aug 16 at 14:18

1 Answer 1

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R' D R F D F' U' F D' F' R' D' R U

The idea is to take out a corner from the top layer and put it back with a different rotation. This can be done in 6 moves (R' D R F D F'). Then you turn the top layer and do the same move backwards. The move backwards applies the opposite rotation to a different corner and restores the rest of the cube. Finally turn the top layer back.

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  • $\begingroup$ Great answer. I forgot about the front layer since I seldom use it (I am not very coordinated so I avoid turning the front, back, and left sides). $\endgroup$
    – JHB
    Aug 16 at 14:13
  • $\begingroup$ Same here. It is the shortest I know in number of moves, but not the fastest to execute for me. $\endgroup$
    – Florian F
    Aug 16 at 14:22
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    $\begingroup$ I got it down to 13 with a little more playing. This one also requires moving the front face (R’ b R2 T’ R2 b’ R’ T R2 B’ F2 B F2). $\endgroup$
    – JHB
    Aug 17 at 21:14

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