Currently stuck on Super Picross and looking for a hint for the next logical deduction on Mario stage SP-I.

Mario stage SP-I


2 Answers 2


A deduction for either side column:

The second-from side columns can have runs of maximum length 2. Therefore, the 5 and 3 on the side columns must use a row which has an ending run of length 1. For the 3, this may happen anywhere. For the 5, there must be 1s in sufficient places such that no 3-length section of the 5 passes through rows which all have starting runs of length >1.

For example:

If the leftmost-column's run of 5 is placed in the top of the un-Xed place (rows 3-8), each of the rows it passes through have a starting run of length >1. Therefore each row will extend a run out of the 5, moving to columns further right. However, since all rows extend, the second-from-left column will have a run of 5, which is not allowed.

This gets you to:


If you need a little further, try applying similar logic to:

the top row

with the important modification that

only columns with length >2 need be considered bad, and now it is runs of 4 bad columns which are disallowed.

  • $\begingroup$ If this isn't far enough, Sam, please tell me and I'll delete it $\endgroup$
    – bobble
    Commented Mar 19, 2022 at 23:53
  • $\begingroup$ It’s good enough. $\endgroup$
    – Sam Y
    Commented Mar 22, 2022 at 22:02


You can determine the position of the 7 in the second row.



Why? Otherwise, we can deduce the following sequence.


first deduction


second deduction


third deduction


this creates a group of 4 in the third row.


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.