# Alchemistry - A study on alchemy (Author Note) A while ago I made some puzzles for a now defunct puzzle hunt project, here's one of them. The answer to this (and most other puzzles of said hunt) is a single word. The puzzle itself is fully contained within the image above. Author notes don't matter.

The symbols are

We can convert to

the atomic number of each element

to transform the statements into

1. 6 (carbon) + 3⦶ = 50 (tin)
2. 82 (lead) + 🜔 = 83 (bismuth)
3. 50 (tin) + ⦶ = 82 (lead)
4. 51 (antimony) + ⦶ - 4🜔 = 79 (gold)
5. 47 (silver) - ⦶ = 29 (copper)
6. 77 (iridium) + 2🜔 = 79 (gold)
7. 79 (gold) - ⦶ = 47 (silver)

We can think of each of these statements as performing alchemy as follows:

Starting with one element, apply some transformations to obtain a different element.

Based on statements 2 and 6, we can infer that

Applying a multiple of 🜔 changes the element's atomic number by that multiple.

Turning our attention to statements 3, 4, and 7, it appears that

Applying a multiple of ⦶ changes the element's atomic number by that multiple of 32.

Finally, from statements 1 and 5, we learn that

Applying ⦶ still results in a large change, but with a smaller magnitude than 32.

These rules could be visualized if

we placed the elements in unequal rows based on atomic number and viewed 🜔 and ⦶ as horizontal and vertical movement, respectively.

Of course, there is a well known way to do this:

This gives us the proper way to interpret the 7 statements:

1. Carbon (6 C) shifted down by 3 yields tin (50 Sn).
2. Lead (82 Pb) shifted right by 1 yields bismuth (83 Bi).
3. Tin (50 Sn) shifted down by 1 yields lead (82 Pb).
4. Antimony (51 Sb) shifted down by 1 and left by 4 yields gold (79 Au).
5. Silver (47 Ag) shifted up by 1 yields copper (29 Cu).
6. Iridium (77 Ir) shifted right by 2 yields gold (79 Au).
7. Gold (79 Au) shifted up by 1 yields silver (47 Ag).

Turning our attention to the unanswered statements at the end of the puzzle, we can convert and transform them as follows:

1. Bismuth (83 Bi) shifted right by 1 yields polonium (84 Po).
2. Silver (47 Ag) shifted left by 5 and down by 1 yields tungsten (74 W).
3. Samarium (62 Sm) shifted right by 6 yields erbium (68 Er).

Finally, we can

combine the resulting chemical symbols (Po, W, Er)