16
$\begingroup$

I don't know why I even took this class. All the math is so complicated. We were learning order of operations and then I get this monstrosity. Can you help me do it?

$(3+4)(2-3)=18-1$
$(2-7)^2+(1-5)=-44-33$
$(5-1)(9+8)=53+31$
$(6-2)^2-(10-13)= \ ?$

$\endgroup$

1 Answer 1

20
$\begingroup$

The answer is

$22-11$

since the "complicated" math is in fact

complex (kind of a synonym for complicated) number arithmetics with $i$'s omitted (one can easily guess that since all the numbers come in pairs, joined with plus or minus signs)

So far

$(3+4i)(2-3i)=18-1i$
$(2-7i)^2+(1-5i)=-44-33i$
$(5-1i)(9+8i)=53+31i$
$(6-2i)^2-(10-13i)=22-11i$

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.