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A notorious serial killer going by the pseudonym "N" has dispatched a letter to the FBI after committing 45 homicides. He is characterized to be extremely intelligent and sends mysterious cryptographic letters to the police once a month, for the mere reason being "messing around".

This time, the letter received was;

Dear informants, 
I know you want me, and you know I want you too.
But are you a genius?
You gotta have some genius to catch me.
And you know what? I am sad...You have about a thousand suspects of me.
And none of them is me! 
I am depressed to see such failure, specially by the glorious FBI.
So, below....is some crypted content. In the content, contains my full name.
If you solve it, you win! And I? Well...I lose. Unfortunately...
You'll try.

BQzkmcmaIJSaiNysehtMtlzqUScmtz

Sincerely,
N

What is his name?

Hint:

The encrypted text contains the name in the format, "MyNameIs[XYZ]". The first letters of the last and first name may or may not be capitalized.

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    $\begingroup$ So tempting to post a troll answer saying "no, I'm not" :-p Cool username btw! $\endgroup$
    – Rand al'Thor
    Mar 28, 2015 at 19:57
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    $\begingroup$ In these situations, it's always Rumplestiltskin, no? $\endgroup$
    – Lopsy
    Mar 28, 2015 at 21:35
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    $\begingroup$ What if his name is actually BQzkmcmaIJSaiNysehtMtlzqUScmtz and he became a serial killer because other people used to tease him? $\endgroup$
    – leoll2
    Mar 29, 2015 at 9:04
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    $\begingroup$ Ofcourse not! The name is composed of many two names; the first and last name. There is no middle name involved. XYZ was merely an example to feed your curiosity. $\endgroup$
    – Kalis
    Mar 29, 2015 at 15:05
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    $\begingroup$ Am I the only who noticed that the letters of MyNameIs are all contained inside the string, also respecting upper and lowercase? So, that may be an anagram, though the scarcity of remaining vowels makes the task even harder. $\endgroup$
    – leoll2
    Mar 29, 2015 at 15:39

3 Answers 3

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Start with:

BQzkmcmaIJSaiNysehtMtlzqUScmtz

Remove MyNameIs:

BQzk cm JSai ht tlzqUScmtz

Group the remaining letters:

  • First letters: BJQSSU
  • Vowels: ai
  • Others: cchklmmqttzzz

Make a name with them:

Jack Smith

Remove its letters:

BQz tlzqUScmtz

Nice.

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    $\begingroup$ Holy crab, I accidentally wrote John Smith in one of the comments, if this is correct, I was unintentionally damn close! By the way, it would be sad if the left letters were there just to be discarded without criterion... $\endgroup$
    – leoll2
    Mar 29, 2015 at 19:26
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    $\begingroup$ You solved it purely like a chess grandmaster, Miguel! Congratulations. I added an answer which will further elucidate the solution. $\endgroup$
    – Kalis
    Mar 29, 2015 at 19:48
  • $\begingroup$ Too smart! Impressive explanation to the answer! $\endgroup$
    – Nai
    Nov 20, 2015 at 3:26
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Miguel solved the puzzle but not completely, I'll further elucidate.

The value is;

BQzkmcmaIJSaiNysehtMtlzqUScmtz

And as the hint states, the killer's name will start off with "MyNameIs" and where is this? The letters of "MyNameIs" and the killer's name are located exquisitely here;

BQzkmcmaIJSaiNysehtMtlzqUScmtz

So, we'll take em' out to grab the answer:

kmcmaIJSaiNysehtM

Then, after taking out the letters of "MyNameIs", we're left with:

kmcaJSiht

Eureka! After assorting it in a proper order, The killer's name is;

JackSmith

And the complete hidden text was:

MyNameIsJackSmith
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It is unlikely that 9 characters of the name should be upper case. It is also unlikely that the name length is 30 characters. Therefore the killer's name is:

one of these 16 names that use about half of the characters from the encryted string:

Mateusz Michalski
Michal Stantejsky
Matthias Kuntzel
Michael Stickman
Sebastian Schulz
Shamus McClaskey
Timea Bacsinszky
Chaim Maltinsky
Helmut Bakaitis
Hikmet Sulayman
Jacques Bialski
Jacques Cassini
Jacques Haitkin
James McQuilkin
Klaus Steinbach
Maciej Szmatiuk

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  • $\begingroup$ A marvelous attempt, but wrong. None of the names listed match, or even slightly close to the killer's name. $\endgroup$
    – Kalis
    Mar 29, 2015 at 15:08

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