Pythonic Purity Puzzle

Question

You are looking for a ten-letter word.

Perfection is displayed not when there is nothing left to add, but when there is nothing left to take away.

  1 matter = []; matter.append('857'); matter.append(str(wrench)[8:]);                      matter.append('38479')

  2 import math, sys, random, glob, pickle

  3 tool = int(matter[0]+matter[1]+matter[2])

  4 String gear == (duble(5/5)+math.pi[4])/3

  5 whilis(true):

  6     print(random.randnums())

  7     tol += 5++

  8     for bit in piece: print(chr(int(bit)))

  9 aluminum = [[str(turn)[index:index + 2] for index in range(0, len(str(turn)), 2)]       for turn in cycle]

  10 sprocket = [x for x in range(lower, 'a')]

  11 machine = []; machine.append('6');machine.append(str(tool)[2:4]);                      machine.append('2658283')

  12 wrench = math.floor(2.3)*11*13*math.isqrt(289)*67*(111**2+106**2)

  13 cycle = [wrench, tool, lever]

  14 if a|b: print(a||b)

  15 elsif: print(a&&b)

  16 _='_=%rrint (_%%_)';print (__)

  17 ferrum = math.lowerbound(523) + 612 + 3.0 + (5.0, 3, 3)

  18 pickle.dump('stock', 53)

  19 lever = int(machine[0]+machine[1]+machine[2])

  20 for piece in aluminum: 
 
  21     int cam = "five"

  22 switch(cam):

  23     case (cam == 5):

  24         print(5);;

  25     alse:

  26         solution = [&%"trgevqbsrireloebxrayvar"]

Answer 1

Full Solution

1 matter = []; matter.append('857'); matter.append(str(wrench)[8:]);                      matter.append('38479')
2 import math, sys, random, glob, pickle
3 tool = int(matter[0]+matter[1]+matter[2])
4 String gear == (duble(5/5)+math.pi[4])/3
5 whilis(true):
6     print(random.randnums())
7     tol += 5++
8     for bit in piece: print(chr(int(bit)))
9 aluminum = [[str(turn)[index:index + 2] for index in range(0, len(str(turn)), 2)]       for turn in cycle]
10 sprocket = [x for x in range(lower, 'a')]
11 machine = []; machine.append('6');machine.append(str(tool)[2:4]);                      machine.append('2658283')
12 wrench = math.floor(2.3)*11*13*math.isqrt(289)*67*(111**2+106**2)
13 cycle = [wrench, tool, lever]
14 if a|b: print(a||b)
15 elsif: print(a&&b)
16 _='_=%rrint (_%%_)';print (__)
17 ferrum = math.lowerbound(523) + 612 + 3.0 + (5.0, 3, 3)
18 pickle.dump('stock', 53)
19 lever = int(machine[0]+machine[1]+machine[2])
20 for piece in aluminum: 
21     int cam = "five"
22 switch(cam):
23     case (cam == 5):
24         print(5);;
25     alse:
26         solution = [&%"trgevqbsrireloebxrayvar"]

The string in the last line…

reads "getridofeverybrokenline" in rot13

If we do that we are left with:

1 matter = []; matter.append('857'); matter.append(str(wrench)[8:]);matter.append('38479')
2 import math, sys, random, glob, pickle
3 tool = int(matter[0]+matter[1]+matter[2])
8     for bit in piece: print(chr(int(bit)))
9 aluminum = [[str(turn)[index:index + 2] for index in range(0, len(str(turn)), 2)] for turn in cycle]
11 machine = []; machine.append('6');machine.append(str(tool)[2:4]); machine.append('2658283')
12 wrench = math.floor(2.3)1113*math.isqrt(289)67(1112+1062)
13 cycle = [wrench, tool, lever]
19 lever = int(machine[0]+machine[1]+machine[2])
20 for piece in aluminum:

These are syntactically valid, but they are out of order, we reorder the statements based on which statement uses the results of which other statements. Since it's python we put the import at the top:

2 import math, sys, random, glob, pickle

Then wrench doesn't depend on anything else so put that next:

12 wrench = math.floor(2.3)1113*math.isqrt(289)67(1112+1062)

matter depends only on wrench so it's next:

1 matter = []; matter.append('857'); matter.append(str(wrench)[8:]);matter.append('38479')

tool depends only on matter:

3 tool = int(matter[0]+matter[1]+matter[2])

machine depends on tool:

11 machine = []; machine.append('6');machine.append(str(tool)[2:4]); machine.append('2658283')

lever depends on machine:

19 lever = int(machine[0]+machine[1]+machine[2])

cycle depends on wrench, tool, lever:

13 cycle = [wrench, tool, lever]

aluminum depends on cycle:

9 aluminum = [[str(turn)[index:index + 2] for index in range(0, len(str(turn)), 2)] for turn in cycle]

Now the for loop can be put:

20 for piece in aluminum:
8     for bit in piece: print(chr(int(bit)))

Now run this code in the python shell:

import math, sys, random, glob, pickle
wrench = math.floor(2.3)1113*math.isqrt(289)67(1112+1062)
matter = []; matter.append('857'); matter.append(str(wrench)[8:]);matter.append('38479')
tool = int(matter[0]+matter[1]+matter[2])
machine = []; machine.append('6');machine.append(str(tool)[2:4]); >!machine.append('2658283')
lever = int(machine[0]+machine[1]+machine[2])
cycle = [wrench, tool, lever]
aluminum = [[str(turn)[index:index + 2] for index in range(0, len(str(turn)), 2)] for turn in cycle]
for piece in aluminum:
  for bit in piece: print(chr(int(bit)))

It prints:

LINENUMBERSARECHARS

Take the line numbers:

2,12,1,3,11,19,13,9,20,8 and those are BLACKSMITH in the alphabet