# The next steps for this Kakuro puzzle

What are the next steps for this Kakuro? I've solved most of it, but there is an area I'm stuck on. Source: Puzzle Page app

11 in four has got to be $$1,2,3,5$$ in some order. The top one must be $$2$$ or $$4$$, so now you know it must be $$2$$.
Then the $$5$$ in that column can only be in two places. Trying it in the upper possibility (just below the $$2$$) leads to a contradiction in the column to the left of that (two cells must be $$1$$ and $$3$$, we already have a $$4$$ above, so the remaining cell must be another $$5$$, contradiction). So the $$5$$ is placed, and then everything else should follow easily.
• @Kidburla A general principle of Kakuro is that the smallest and largest possible sum-in-n always have just one possibility (like $10$ in four must be $1,2,3,4$ while $30$ in four must be $9,8,7,6$), so do the second smallest and second largest ($11$ in four must be $1,2,3,5$ while $29$ in four must be $9,8,7,5$), then the third smallest and third largest have two possibilities ($12$ in four must be $1,2,3,6$ or $1,2,4,5$ while $28$ in four must be $9,8,7,4$ or $9,8,6,5$). Jun 21, 2021 at 23:03