4
$\begingroup$

The 4 rows of words in the table below are each formed by following one rule.

Group Word 1 Word 2 Word 3
1 save scar trap
2 adore argue boy
3 cool dummy married
4 lovely mockery underdog

What is the rule?

Hint 1:

Think of this as a mathematical problem. The group numbers, they're pretty small to be math solutions right? Maybe take them as tens?

Hint 2:

Keyboard arrangement.

Improve this question
$\endgroup$

4 Answers 4

Reset to default
4
$\begingroup$

Putting the two hints together gives a straightforward answer:

Treating the row #'s as 10's and assigning each letter a value equal to the digit above it on a keyboard (Q,A,Z=1 etc) we see the rows were created by finding words that sum to that row # (* 10) (the words were then placed in alphabetical order).
First Example: S2 A1 V4 E3 = 10 (row 1)
Last Example: U7 N6 D3 E3 R4 D3 O9 G5 = 40 (row 4)

Improve this answer
$\endgroup$
1
$\begingroup$

Partial Answer

Here is a very easy answer:

Each group is in alphabetical order.

If that is just on purpose, here is another answer:

Every first letter in word 1, word 2, word 3, are consecutive numbers according to Scrabble tile points.

For example:

SACL (Word 1) scores 6 points. SADM scores 7 points. The last one is TBMU, which scores 8.

Improve this answer
$\endgroup$
3
  • 1
    $\begingroup$ You've got the word1, word2, word3 order right, but it still doesn't explain the grouping rule :D $\endgroup$
    – risky mysteries
    Jun 6, 2021 at 12:39
  • $\begingroup$ I'll try to figure out.. $\endgroup$
    – IsaacRoan Sison
    Jun 6, 2021 at 12:40
  • $\begingroup$ Time to wait for a hint! $\endgroup$
    – IsaacRoan Sison
    Jun 6, 2021 at 12:50
0
$\begingroup$

the group number for each group is (almost) the the tens place of the total score.

save (7) + scar (6) + trap (6) = 19

adore (6) + argue (6) + boy (8) = 20

cool (6) + dummy (13) + married (10) = 29?

lovely (12) + mockery (18) + underdog (11) = 41

It's clearly not quite right... but it's close?

Improve this answer
$\endgroup$
-3
$\begingroup$

Group 3 - each word has a Sequentially repeated letter

another option.. in each group, words 1,2,3 are in alphabetical order?

Improve this answer
$\endgroup$
3
  • $\begingroup$ Hi, welcome to PSE! I believe you missed it, but as pointed out in my post, the 4 groups of words all have one property on common, and a repeated letter does not apply to all of them. $\endgroup$
    – risky mysteries
    Jun 6, 2021 at 1:07
  • $\begingroup$ @riskymysteries Is getting the groups' properties and then finding the relation through them leads to an answer? (like a connect wall) $\endgroup$
    – IsaacRoan Sison
    Jun 6, 2021 at 4:31
  • $\begingroup$ @IsaacRoanSison The answer to this puzzle is finding out what one rule makes each group. $\endgroup$
    – risky mysteries
    Jun 6, 2021 at 12:06

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.