Can you fill a 4x4 grid with every number from 1 to 16, such that every row, every column and every 2x2 sub-grid of numbers sum to the same value?
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asked Apr 6 at 2:19
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Solution:
1 15 2 16 14 4 13 3 7 9 8 10 12 6 11 5
Notes:
A B C D E F G H I J K L M N O P
Must have
A+B = G+H = I+J = O+P
C+D = E+F = K+L = M+N
A+E = J+N = C+G = L+P
I+M = B+F = K+O = D+H
B+C = J+K = E+H = M+P
F+G = N+O = A+D = I+L
E+I = G+K = B+N = D+P
F+J = H+L = A+M = C+O
which are enough constraints to make it manageable by trial and error.
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$\begingroup$ For more information on this topic see this: en.wikipedia.org/wiki/Most-perfect_magic_square $\endgroup$ Apr 8 at 3:04
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This one has a kind of rhythm I find cool:
| 1 | 16 | 2 | 15 |
| 14 | 3 | 13 | 4 |
| 12 | 5 | 11 | 6 |
| 7 | 10 | 8 | 9 |
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$\begingroup$ @loopywalt thats correct, my mistake, I forgot to consider this one. It appears that exchanging rows 3 and 4 fixes it. Then it is interesting to note that it gives a solution similar to yours but with columns 2 and 4 exchanged. So it seems there are not plenty of solutions... $\endgroup$– FredApr 12 at 15:05
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| 1 | 16 | 5 | 12 |
| 8 | 9 | 4 | 13 |
| 3 | 14 | 7 | 10 |
| 15 | 2 | 11 | 6 |
Each 2x2 square should be (largest + smallest) * 4 / 2. In this case that would be 34.
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6$\begingroup$ You forgot the columns, they don't add up properly. $\endgroup$ Apr 6 at 14:22
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